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kaheart [24]
3 years ago
8

3(Log(x) + Log(2)) - Log(2)

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

Here you go, I found this on google.

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How do I solve this
ra1l [238]
-2+(-5)=-7 and 6+(-3)=3
5 0
4 years ago
Please help fast......
Tom [10]

3)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}

*************************************************************************************

6)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}

*************************************************************************************

7)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}

5 0
4 years ago
David borrowed $30,000 to start a business. Four years later he repaid $1260 in interest. What was the annual rate? Round to two
ollegr [7]
Annual rate = 1.05%

Simple interest formula is I = Prt * 100
Where P is principle, I is interest, r is rate and t is time.

Transpose to make r the subject

Prt * 100 = I
r = I/ Pt * 100

Substitute values into the equation.
Let I = $1260, P = $30,000 and t = 4 years

r = $1260/ $30,000 * 4 * 100
r = 0.0105 * 100
r = 1.05%
5 0
3 years ago
If one out of 12 students at a school share a locker how many share a locker in a school of 456
Kobotan [32]

Answer:

456/12= 38  means 38 kids share a locker

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
X^2(x^2+3x+2)plzz help me
agasfer [191]

The zeros for this function are -2, -1 and a double root of 0.

You can find this by first factoring the polynomial on the inside of the parenthesis. Polynomials like this can be factored by looking for two numbers that multiply to the constant (2) and add up to the second coefficient (3). The numbers 2 and 1 satisfy both of those needs and thus can be used as the numbers in a factoring.

x^2(x^2 + 3x + 2)

x^2(x + 2)(x + 1)

Now to find the zeros, we set each part equal to 0. You may want to split the x^2 into two separate x's for this purpose.

(x)(x)(x + 2)(x + 1)

x = 0

x = 0

x + 2 = 0

x = -2

x + 1 = 0

x = -1

8 0
3 years ago
Read 2 more answers
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