Answer:
132 m
Step-by-step explanation:
Refer to attachment for figure.
In smaller triangle with angle theta , we have ,
⇒ tanθ = p/b
⇒ tanθ = h/121m
⇒ tanθ = h/121 m
<u>In</u><u> </u><u>triangle</u><u> </u><u>with</u><u> </u><u>angle </u><u>9</u><u>0</u><u>-</u><u>∅</u>
⇒ tan(90-θ) = p/b
⇒ cot θ = h/144 m
Multiplying these two ,
=> tanθ . cotθ = h/121 m × h/144m
=> 1 = h²/ (121 m × 144m )
=> h² = 121m × 144m
=> h= √ ( 121m × 144m)
=> h = 11m × 12m
=> h = 132 m
Answer:
87.73 inches
Step-by-step explanation:
We are given that the dimensions of the rectangular doorway are,
Length = 6 ft 8 inches = 80 inches and Width = 3 feet = 36 inches.
Using Pythagoras Theorem, we will find the diagonal of the rectangular doorway.
i.e.
i.e.
i.e.
i.e.
i.e. Hypotenuse = ±87.73 inches
Since, the length cannot be negative.
So, the length of the diagonal is 87.73 inches.
As, the largest side of a rectangle is represented by the diagonal.
So, the largest dimension that will fit through the doorway without bending is 87.73 inches.