Answer:
The solutions are
and 
Step-by-step explanation:
we have

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

Complete the square. Remember to balance the equation by adding the same constants to each side.


Rewrite as perfect squares


square root both sides





the answer is y=2x-3
You can look at my work if you really need to
Answer:
your are a fatherless child ligma nuz
Step-by-step explanation:
Answer: The expressions for the length and width of the new patio are

And the area of the new patio is 384 sq. feet.
Step-by-step explanation: Given that Stephen has a square brick patio. He wants to reduce the width by 4 feet and increase the length by 4 feet.
The length of one side of the square patio is represented by x.
We are to write the expressions for the length and width of the new patio and then to find the area of the new patio if the original patio measures 20 feet by 20 feet.
Since Stephen wants to reduce width of the patio by 4 feet, so the width of the new patio will be

The length of the patio is increased by 4 feet, so the length of the new patio will be

Now, if the original patio measures 20 feet by 20 feet, then we must have

and

Therefore, the area of the new patio is given by

Thus, the expressions for the length and width of the new patio are

And the area of the new patio is 384 sq. feet.
If tangent to the curve y = √x is parallel to the line y = 8x, then this implies that the tangent to y = <span>√x has the same slope as the line y = 8x. In other words, the derivative (slope) function of y = √x is equal to the slope of the line y = 8x, which is m = 8. Hence y' = 8 once we find y'
y = </span><span>√x = x^(1/2)
Applying the power rule and simplifying, we find that the derivative is
y' = 1/(2</span>√x)
Now remember that y' must equal 8
1/(2<span>√x) = 8
Multiplying both sides by 2</span><span>√x, we obtain
1 = 16</span><span>√x
Dividing both sides by 16, yields
</span><span>√x = 1/16
But wait a minute, √x = y. Thus 1/16 must be the y-coordinate of the point at which the tangent to y = √x is drawn.
Squaring both sides, yields
x = 1/256
This is the x-coordinate of the point on the curve where the tangent is drawn.
</span><span>∴ the required point must be (1/256, 1/16)
GOOD LUCK!!!</span>