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3 years ago

IS THIS RIGHT??? PLEASE HELP ASAP

Mathematics

2 answers:

yulyashka [42]3 years ago

5 0

Answer:

5 units right is the correction you need

Step-by-step explanation:

marusya05 [52]3 years ago

3 0

Answer:

Its 5 units up and 4 units to the left

Step-by-step explanation: If wrong just lmk

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34Step-by-step explanation:

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3 years ago

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3 years ago

Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

$\sqrt{11-2x}=\sqrt{x^{2}+4x+4}$

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

$\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}$

$\sqrt{25}=\sqrt{25}$

$5=5$ ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

$\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}$

$\sqrt{9}=\sqrt{9}$

$3=3$ ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0

3 years ago

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