The question is missing the alternatives. Here is the complete question.
A ricksaw company counted 39 ticket receipts last week. The price for a weekday ticket is $7, and the price for a weekend ticket is $9.50. The ricksaw driver collected a total of $333 for the week. Let x represent the number of weekend tickets and y represent the number of weekday tickets. Which system of equations represents the situation?
a) y = x + 39
14y = - 19x + 666
b) y = - x + 39
15y = - 19x + 666
c) y = - x + 39
15y = 19x + 666
d) y = - x + 39
14y = - 19x + 666
e) y = x + 39
7y = - 9x + 333
Answer: d) y = - x + 39
14y = - 19x + 666
Explanation: X represents the number of weekend tickets, then the cost of all the tickets on the weekend is: 9.5x
Y is for weekdays, so the cost for all the tickets on the weekdays is: 7y
The company counted a total of 39 tickets: x + y = 39
Isolating y:
The number of total tickets:
x + y = 39
y = - x + 39
The total cost:
7y + 9.5x = 333
7y = - 9.5x + 333
Turning the coefficients an integer:
2.7y = 2.(-9.5)x + 2.333
14y = - 19x + 666
The equations that represent the situation are:
y = - x + 39
14y = - 19x + 333
