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VLD [36.1K]
3 years ago
15

-4x^2-12x+1 find the standard form

Mathematics
1 answer:
34kurt3 years ago
3 0
I'd stay this expression is already in standard form, although you could rewrite it as   -(<span>-4x^2-12x+1).

You could rewrite   </span><span>-4x^2-12x+1    by completing the square:

-4(x^2 + 3x                    )                         +1  becomes

-4(x^2 + 3x + [3/2]^2     )       - [3/2]^2       + 1, or

-4(x + 3/2)^2           + 1 - 9/4,    or

-4(x+3)^2      -5/4    (final form)     The graph would be that of a parabola with vertex at (-3, -5/4).  This parabola would open down and would be vertically stretched by a factor of 4.</span>
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Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

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m = (y2 - y1)/(x2 - x1)

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x2 = final value of x

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The answer is A to the question
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