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3 years ago

8

How would 5,708,942,013 be written in word form?

2 answers:

harkovskaia [24]3 years ago

4 0

Answer:

$~Hi,~There!$

How would 5,708,942,013 be written in word form?

A. five million, seven hundred eight thousand, nine hundred forty-two thousand, thirteen

Hope this helps!

MatroZZZ [7]3 years ago

3 0

Answer:five billion, seven hundred and eight million, nine hundred and forty two thousand and thirteen

Step-by-step explanation:

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Adam sold 40% of the 70 chocolate bars he has to sell for his school fundraiser. How many does Adam still have to sell? Provide

Karolina [17]

Answer:

C

Step-by-step explanation:

Given that he has sold 40% then he still has to sell (100 - 40)% = 60%

60% of 70

= $\frac{60}{100}$ × 70 = 0.6 × 70 = 42 → C

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3 years ago

Emely has 25 onions and 14 peppers that she grew in her garden. homw many more oinons does she have that peppers

stiks02 [169]

Answer:

11

Step-by-step explanation:

<u><em>SUBTRACT</em></u>

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3 years ago

In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm

tangare [24]

Answer:

$AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm$

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

$AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm$

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

$\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD$

Consider right triangle CAH.By the Pythagorean theorem,

$CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8$

The length cannot be negative, so CD=8 cm and

$CA=\sqrt{3}CD=8\sqrt{3}\ cm$

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

$AB=2CA=16\sqrt{3}\ cm$

By the Pythagorean theorem,

$BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm$

3 0

3 years ago

Solve the following system of equations:

antoniya [11.8K]

I think the answer is B

8 0

3 years ago

Read 2 more answers

What is the answer for number 8 and pls give step by step

Pie

Answer:

Trapezoid 1 (left side):

Base 1 = 2

Base 2 = 5

Trapezoid 2 (right side):

Base 1 = 6

Base 2 = 8

Step-by-step explanation:

<u>1st trapezoid:</u>

b_1 = x

b_2 = x + 3

h = 4

Hence, area (from formula) would be:

$A=\frac{h}{2}(b_1+b_2)\\A=\frac{4}{2}(x+x+3)\\A=2(2x+3)\\A=4x+6$

<u>2nd trapezoid:</u>

b_1 = 3x

b_2 = 4x

h = 2

Putting into formula, we get:

$A=\frac{h}{2}(b_1+b_2)\\A=\frac{2}{2}(3x+4x)\\A=1(7x)\\A=7x$

Let's equate both equations for area and find x first:

$4x+6=7x\\6=7x-4x\\6=3x\\x=\frac{6}{3}\\x=2$

We can plug in 2 into x and find length of each base of each trapezoid.

Trapezoid 1 (left side):

Base 1 = x = 2

Base 2 = x + 3 = 2 + 3 = 5

Trapezoid 2 (right side):

Base 1 = 3x = 3(2) = 6

Base 2 = 4x = 4(2) = 8

8 0

3 years ago