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avanturin [10]
3 years ago
10

What is the probability of getting tails 4 times in a row while flipping a coin?

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

P=0.0625

Step-by-step explanation:

The probability of getting one tails is a half.

The probability of getting another tails given you had a tails is:

\frac{1}{2}*\frac{1}{2}=(\frac{1}{2})^2=\frac{1}{4}

The probability of getting n tails in general is given by:

(\frac{1}{2})^n = \frac{1}{2^n}

So, when we have four tails - our value for n is four.

(\frac{1}{2})^4=\frac{1}{2^4}=\frac{1}{16}=0.0625

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Answer: Yes, The relation is a function, they are the exact opposite.

Step-by-step explanation:

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3 years ago
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What two partial products would you add to find 513 x 46
Afina-wow [57]
First, let me do the Mathematical part of that, and then I shall explain the theory behind it.

Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.

Multiply 513 with 6 first.

    513
    x46
--------------------------
      18 (as 6*3 = 18)
      60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
  3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
    120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
    400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)


Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.

Check: If we check the multiplication result by using the calculator, we would get the same result (23598).

Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.
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So
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Hopefully helpfull.. ^_^
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Step-by-step explanation

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