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3 years ago

What is the probability of getting tails 4 times in a row while flipping a coin?

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

7 0

Answer:

$P=0.0625$

Step-by-step explanation:

The probability of getting one tails is a half.

The probability of getting another tails given you had a tails is:

$\frac{1}{2}*\frac{1}{2}=(\frac{1}{2})^2=\frac{1}{4}$

The probability of getting n tails in general is given by:

$(\frac{1}{2})^n = \frac{1}{2^n}$

So, when we have four tails - our value for n is four.

$(\frac{1}{2})^4=\frac{1}{2^4}=\frac{1}{16}=0.0625$

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MrMuchimi

Answer:

$y{x} = \sqrt{7+2Inx}$

Step-by-step explanation:

$y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}$

Let say; By y(x)= y(e)

we have;

$y(e)= 3 + \int\limits^e_e {dt}/ \, ty= 3+0$

Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

$y^{1} (x) = 0 + 1/ xy$

$y^{1} = 1/xy$

dy/dx = 1/xy

$\int\limits {y} \, dxy = \int\limits \, dx/x$

$y^{2}/2 Inx + C$

RECALL: y(e) = 3

$(3)^{2} / 2 = In (e) + C$

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$\frac{9}{2} - 1 = C$

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$y^{2} / 2 = In x +C$

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3 years ago

Bryan has a bag containing 12 red marbles, 8 blue marbles, 5 green marbles and 3 yellow marbles. He will randomly select one mar

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Step-by-step explanation:

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3 years ago

A certain substance in an experiment was being stored at −2.4°F. It was then placed on a table where the temperature was raised

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Step-by-step explanation:

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2 years ago

The sale bin in a clothing store contains an assortment of t-shirts in different sizes. There are 7 small, 8 medium, and 4 large

umka21 [38]

Answer:

P(at least 1 large) = 0.648

P(at least 1 large) = 64.8%

Step-by-step explanation:

We have 7 small shirts, 8 medium shirts and 4 large shirts

Total number of shirts = 7 + 8 + 4 = 19 shirts

The probability that at least one of the first four shirts he checks is a large is given by

P(at least 1 large) = 1 - P(no large)

So first we need to find the probability that the none of the first four shirts he checks are large.

For the first check, there are 15 small and medium shirts and total 19 shirts so,

15/19

For the second check, there are 14 small and medium shirts and total 18 shirts left so,

14/18

For the third check, there are 13 small and medium shirts and total 17 shirts left so,

13/17

For the forth check, there are 12 small and medium shirts and total 16 shirts left so,

12/16

the probability of not finding the large shirt is,

P(no large) = 15/19*14/18*13/17*12/16

P(no large) = 0.352

Therefore, the probability of finding at least one large shirt is,

P(at least 1 large) = 1 - P(no large)

P(at least 1 large) = 1 - 0.352

P(at least 1 large) = 0.648

P(at least 1 large) = 64.8%

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2 years ago