Answer:
the total amount of water supplier per hour to the region within a circle of radius R=110 ( that is from distance r, 0<r<110)
![W(R) = 2\pi [1-(R+1)e^{-R}]](https://tex.z-dn.net/?f=W%28R%29%20%3D%202%5Cpi%20%5B1-%28R%2B1%29e%5E%7B-R%7D%5D)
Step-by-step explanation:
if f(r) describes the water supplied at a distance r , the total amount supplied inside a region that goes from 0 until the circle of radius R, is the sum of all f(r) values from 0 until R, that is the integral value over these limits.
The formula deduction can be found in the attached picture
There is an "r" that multiplies e^-r as result of changing from rectangular coordinates to polar ones.(dx*dy --> r*dr*da)
The answer is 3,072.
Heres how I got it:
SA of a CUBE: s^3 * 6
Lets plug in our numbers-
8 * 8 * 8= 512 * 6
512 * 6= 3072
<span><span><span><span>−<span>2<span>(<span>q−22</span>)</span></span></span>+q</span>+12</span>>0</span>
Step 1: Simplify both sides of the inequality.<span><span><span>
−q</span>+56</span>>0</span>
Step 2: Subtract 56 from both sides.<span><span><span><span>
−q</span>+56</span>−56</span>><span>0−56</span></span><span><span>
−q</span>><span>−56</span></span>
Step 3: Divide both sides by -1.<span><span><span>
−q</span><span>−1</span></span>><span><span>−56</span><span>−1</span></span></span><span>
q<56</span>
Answer: q<56
Answer:
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