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Bess [88]
3 years ago
9

Which function represents exponential decay?

Mathematics
1 answer:
horrorfan [7]3 years ago
7 0

the answer to your question would be D

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What was the simple interest rate on a $8,000 Investment that was left in an account for 18 months and earned $360 in Interest?
Karolina [17]
I think it would be 8,228 I think if it is 8000 - 18+360 hopefully I am right
3 0
3 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
Pls help how do i solve for x in this equation??
evablogger [386]

Answer:

x = -2

Step-by-step explanation:

1. Square both sides
x^2 +3x + 6 = x^2
2. Subtract x^2 from both sides
3x + 6 = 0
3. Subtract 6 from both sides and divide by 3
x = -2

6 0
2 years ago
Help me. The last person who answered this question just asked me for personal info.... so please just answer the question...
Lelechka [254]

Answer:

Step-by-step explanation:

so the least common denominator is 12, so:

multiply 3/4ab by three, which equals: 9/12ab

9/12ab-5/12ab = 4/12ab, or 1/3ab

3 0
3 years ago
Which of the following is not something that you could do with a normal checking account
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