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stellarik [79]
3 years ago
9

Help me I need help!

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Answer:

7.D

8.A

Step-by-step explanation:

7.

r=√((0-6)²+(0+8)²)=√(36+64)=√100=10

eq. of circle is (x-6)²+(y+8)²=10²

(x-6)²+(y+8)²=100

8.

CM=1/2CD=1/2×60=30

OM=18

OC=√(30²+18²)=√(900+324)=√(1224)=√(4×306)=√(4×9×34)=2×3√34=6√34

radius r=OC=6√34

OF=r=6√34

ON=15

FN=√((6√34)²-15²)=√(1224-225)=√999=√(9×111)=3√111

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If we wanted to prove quadrilateral MNOP was a parallelogram, which method below would not work?
rjkz [21]

Answer:

The correct option is 4.

4) Doing two distance formulas to show that adjacent sides are not the same length.

Step-by-step explanation:

Parallelogram is a quadrilateral which has opposite sides equals and parallel. Example of a parallelogram are rhombus, rectangle, square etc.

We can prove that a quadrilateral MNOP is a parallelogram. If we find the slopes of all four sides and compare those of the opposite ends, same slopes would indicate the opposite sides are parallel, hence the quarilateral is a parallelogram. We can also find the distance of two opposing sides, and slopes of twp opposing sides to determine whether it is a parallelogram or not. The most difficult approach is that diagonals bisect each other at same point.

However, using only two distance formulas will not give us enough information to determine whether a side is parallel or not.

7 0
3 years ago
What is the slope of <br><br> 12y=(-24)x
White raven [17]

Answer:

-2

Step-by-step explanation:

First, solve so that y is alone on its side of the equation by dividing both sides of the equation by 12.

12y=(-24)x

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3 years ago
15 points!!! GEOMETRY help please!!<br> Questions attached!
dolphi86 [110]
3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o

Answer:\ \boxed{47^o}

4.
Look at the picture.

Use Pythagorean theorem:

x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8

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5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}

We have: OP:\ y=-\dfrac{3}{2}x+b

Now, we must find the slope of the line perpendicular to the line OP.
We know:

k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1

therefore

-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}

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Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}

6 0
2 years ago
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Zielflug [23.3K]

Answer:

option 4.

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Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

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we have to subtract the values ​​of p from s

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h: hypotenuse

c1: leg 1

c2: leg 2

PS^2 = 2^2 + -2^2

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SR = (4 , 4)

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SR^2 = 4^2 + 4^2

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PS * RS = Area

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