How much do 10 pieces of candy cost if 1000 pieces cost $70?

There are 18 oranges in box A and 36 in box B, what is the ratio of box A to box B

Nana76 [90]

Answer:

1 : 2

Step-by-step explanation:

Express the ratio as the number of oranges in each box, that is

box A : box B

= 18 : 36

Simplify the ratio by dividing both parts by 18, thus

ratio = 1 : 2 ← in simplest form

7 0

2 years ago

HELP WITH PROBABILITY PWEASEEE <br> (4 questions)

Aliun [14]

a. {1,2,3,4,5,6}

b. {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. {HH,HT,TH,TT}

d. {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Step-by-step explanation:

We will write the sample space of all options one by one.

a. Rolling a 6 sided die

As the die has six sides numbered from 1 to six then the sample space will be:

S1 = {1,2,3,4,5,6}

b. Guessing the first initial of a student's name:

As the English language has 26 alphabets, the first initial can be any alphabet so the sample space will be all letters:

S2 = {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. Tossing two coins

As two coins are tossed, the outcomes will be a combination of two outcomes

S3= {HH,HT,TH,TT}

d. Rolling a 6 sided die and tossing a coin

As the die is rolled and then a coin is tossed. The die's coin will either combine with heads or tails

So,

S4 = {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Hence,

a. {1,2,3,4,5,6}

b. {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. {HH,HT,TH,TT}

d. {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Keywords: Sample Space, Probability

Learn more about sample space at:

brainly.com/question/11007026

brainly.com/question/11207748

#LearnwithBrainly

8 0

3 years ago

Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights

user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that $\mu = 85, \sigma = 8$