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ANEK [815]
3 years ago
14

Please answer this I will give brainliest thank you very much for your help

Mathematics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

486yd^2

Step-by-step explanation:

Surface area is found by adding all the areas of like shapes.

All of these are the exact same size, so we can just multiply by the number of squares by their area.

So:

A=6(9)(9)\\A=6(81)\\A=486yd^2

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From 16 bagels to 0 bagles percent decrease
Tems11 [23]
Since all are gone it will be 100%
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3 years ago
Find the 8th term in the following geometric sequence. Round your answer to the nearest hundredth. 27/375, 9/75,3/15,1/3,....
Nesterboy [21]

Answer:

  2.57

Step-by-step explanation:

The common ratio of this sequence is ...

  (1/3)/(3/15) = (1/3)/(1/5) = 5/3

Each additional term is 5/3 times the previous one, so the 8th term will be (5/3)^4 times the 4th term (the last one given). It is ...

  (1/3)·(5/3)^4 = 625/243 ≈ 2.57

_____

The generic n-th term (an) is ...

  an = a1·r^(n-1)

where a1 is the first term and r is the common ratio. We can make use of this formula to find the 8th term:

  a8 = (27/375)·(5/3)^7 = (3^3/3^7)·(5^7/(3·5^3)) = 5^4/3^5 = 625/243 ≈ 2.57

7 0
3 years ago
I'm so sorry for whoever answers this, I am really having a brain fart plz help
agasfer [191]

Answer: 1,999,000

Step-by-step explanation:

And yes I made sure it was right

4 0
3 years ago
Read 2 more answers
The sum of two numbers is 54 and the difference is 8. What are the numbers?
timama [110]

Answer:

23 and 31 are the numbers you are searching for.

Step-by-step explanation:

23 + 31 = 54

31 - 23 = 8

Have a nice day!

6 0
3 years ago
A population of rabbits oscillates 19 above and below average during the year, hitting the lowest value in january. the average
Helen [10]

Answer:

p(t)=650+\frac{160}{12}t+19sin(\omega t)

Step-by-step explanation:

The initial value of the population is 650

Each year the population increases 160

The population oscillates 19 above and below.

Due to this information you can assume that the function is:

p(t)=650+\frac{160}{12}t+19sin(\omega t)

where for t=0 p(t)=650

where t=12 160/12 (12) = 160

you can assume that the sinusoidal function has a period of one month. Thus, the population oscillates several times in one year with an amplitu of the oscillation of 19. The, w is:

\omega (1)=2\pi\\\\\omega=2\pi

4 0
3 years ago
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