Question

Let m=x^2-5m=x 2 −5m, equals, x, squared, minus, 5. Which equation is equivalent to (x^2-5)^2-3x^2+15=-2(x 2 −5) 2 −3x 2 +15=−2left parenthesis, x, squared, minus, 5, right parenthesis, squared, minus, 3, x, squared, plus, 15, equals, minus, 2 in terms of m ?

Answer 1

Answer:

• $m^2-3m=-2$
• $m^2-3m+2=0$

Step-by-step explanation:

Let $m=x^2-5$

We want to express the equation $(x^2-5)^2-3x^2+15=-2$ in terms of m.

Given: $(x^2-5)^2-3x^2+15=-2$

Factorizing the third and fourth term, we obtain:

$(x^2-5)^2-3(x^2-5)=-2$

Substituting  $m=x^2-5$, the above equation becomes:

$m^2-3m=-2$

Since the options are not given, the equivalent equation is:

$m^2-3m=-2$

It could also be written in a rearranged form as:

$m^2-3m+2=0$