We know that
the scale is <span>is 1/2 inch = 4 feet
using a graph tool
</span><span>the approximate measurements in the drawing are
</span>5 cm x 4 cm
convert to in
5/2.54--------> 1.97 in
4/2.54------> 1.57 in
convert drawing to actual
if 0.5 in---------> 4 ft
1.97in-------> X
X=1.97*4/0.5------> X=15.76 ft
if 0.5 in---------> 4 ft
1.57 in-------> X
X=1.57*4/0.5------> X=12.56 ft
<span>the approximate area of Quinto's bedroom is 12.56*15.76=197.95 ft</span>²
the answer is
the option C)192 ft²
Answer: (9, -11) ==> point B
Step-by-step explanation:
(4, -3)-(-1, 5)=
(4-(-1), -3-5)=
(4+1, -8)=(5, -8)
(5, -8)+(4,-3)=
(5+4, -8-3)=(9, -11) ==> point B
32 out of 107
Do you trust me?
Circle's Standard Form Equation:
![r^{2} = (x - xo)^{2} + (y - yo)^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D%20%3D%20%28x%20-%20xo%29%5E%7B2%7D%20%2B%20%28y%20-%20yo%29%5E%7B2%7D%20)
First you need to substitute the C (0,-2) in the equation, where: Xo = 0 and Yo = -2;
![r^{2} = (x - 0)^{2} + (y - ( -2))^{2} \\ r^{2} = x^{2} + (y + 2)^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D%20%3D%20%28x%20-%200%29%5E%7B2%7D%20%2B%20%28y%20-%20%28%20-2%29%29%5E%7B2%7D%20%5C%5C%20r%5E%7B2%7D%20%3D%20x%5E%7B2%7D%20%2B%20%28y%20%2B%202%29%5E%7B2%7D%20)
Now you substitute the Point (3,-5) values in the last expression, where: X = 3 and Y = -5;
![r^{2} = 3^{2} + (( - 5) + 2)^{2} \\ r ^{2} = 9 + ( - 3)^{2} \\ r^{2} = 9 + 9 \\ {r}^{2} = 18](https://tex.z-dn.net/?f=r%5E%7B2%7D%20%3D%203%5E%7B2%7D%20%2B%20%28%28%20-%205%29%20%2B%202%29%5E%7B2%7D%20%5C%5C%20r%20%5E%7B2%7D%20%3D%209%20%2B%20%28%20-%203%29%5E%7B2%7D%20%5C%5C%20r%5E%7B2%7D%20%3D%209%20%2B%209%20%5C%5C%20%7Br%7D%5E%7B2%7D%20%3D%2018)
Now you get the R^2 value and substitute in the equation that you found putting the C values on it:
![r^{2} = x^{2} + (y + 2)^{2} \\ x^{2} + (y + 2)^{2} = 18](https://tex.z-dn.net/?f=r%5E%7B2%7D%20%3D%20x%5E%7B2%7D%20%2B%20%28y%20%2B%202%29%5E%7B2%7D%20%5C%5C%20x%5E%7B2%7D%20%2B%20%28y%20%2B%202%29%5E%7B2%7D%20%3D%2018)
Here is your standard form equation of the circle.