<span>We know that the surface of a sphere is: S = 4 * pi * r^2
The surface of Earth is : Se = 4 * 3.1416 * (7900/2)^2 = 196,066,797.51
And the Jupiter is : Sj = 4 * 3.1416 * (88800/2)^2 = 24,772,840,374.32
So the surface of Jupiter is around 11^2 times bigger than the Earth</span>
Answer:
Repeating
Terminating
Repeating
Repeating
Step-by-step explanation:
5 2/7 as improper fraction is 37/7 and it equals 5.28571428571 which makes it repeating because the numbers don't stop.
7/16 is equal to 0.4375 making it terminate because the numbers stop.
14 5/9 as an improper fraction is 131/9 and 131/9 is 14.5555555556 and that is a never ending pattern so it is repeating.
3/22 is equal to 0.13636363636 it is repeating because the numbers never stop.
4x + 3y = 19 multiply this by 4
5x - 4y = 47 multiply this by 3:-
16x + 12y = 76..............(1)
15x - 12y = 141............(2)
Add (1) + (2);-
31x = 217
x = 7
Now plug = 7 into the first equation:-
4(7) + 3y = 19
3y = 19 - 28 = -9
t = -3
Solution is x = 7, y = -3.
Answer:
Step-by-step explanation:
Hello!
Maria and John want to adopt a pet. The animals available for adoption are:
7 Siamese cats
9 common cats
4 German Shepherds
2 Labrador Retrievers
6 mixed-breed dogs
Total pets available: 28
To reach the probability of each pet category you have to divide the number of observed pets for the said category by the total of pets available for adoption:
P(Siam)= 7/28= 0.25
P(Comm)= 9/28= 0.32
P(Ger)= 4/28= 0.14
P(Lab)= 2/28=0.07
P(Mix)= 6/28=0.21
a.
You need to calculate the probability that the selected pet is a cat, this situation includes the categories "Siamese" and "common cat"
P(Cat)= P(Siam) + P(Comm)= 0.25+0.32= 0.57
b.
You have a total of 16 cats out of 28 pets. If you express it in the ratio: 16:28 → using 4 as a common denominator the odds of selecting a cat is: 4:7
c.
P(Cat∪Mix)
The events "cat" and "mixed-breed dog" are mutually exclusive, so you can calculate the probability of the union of both events as:
P(Cat∪Mix)= P(Cat)+P(Mix)= 0.57+0.21= 0.78
d.
Now you are in the situation that they select a dog that is not a labrador, this situation includes the categories " German shepherd" and "mixed-breed"
P(NotLab)= P(Ger)+P(Mix)= 0.14 + 0.21= 0.35
I hope this helps!
