2 years ago

HELP I DONT KNOW THESE :(

Mathematics

1 answer:

Leya [2.2K]2 years ago

5 0

The answer is -1 and 2

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A secant and a tangent to a circle intersect in a 42-degree angle. The two arcs of the circle intercepted by the secant and the

Amanda [17]

Answer:

The measure of the third arc is $150\°$

Step-by-step explanation:

step 1

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

in this problem

Let

x----> the greater arc of the circle intercepted by the secant and the tangent

y----> the smaller arc of the circle intercepted by the secant and the tangent

$42\°=\frac{1}{2}(x-y)$

$84\°=(x-y)$ ----> equation A

$\frac{x}{y}=\frac{7}{3}$

$x=\frac{7}{3}y$ -----> equation B

Substitute equation B in equation A and solve for y

$84\°=(\frac{7}{3}y-y)$

$84\°=(\frac{4}{3}y)$

$y=3*84\°/4=63\°$

Find the value of x

$x=\frac{7}{3}(63\°)=147\°$

step 2

Find the measure of the third arc

Let

z------> the measure of the third arc

we know that

$x+y+z=360\°$ -----> complete circle

substitute the values and solve for z

$147\°+63\°+z=360\°$

$z=360\°-(147\°+63\°)=150\°$

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S is the midpoint of TV. TS = 4x - 7, and SV = 5x - 15. Find TS, SV, and TV.

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Step-by-step explanation:

TS = 4x - 7

x = -7/4

SV = 5x -15

x = -15/5

= -3

TV = -7/4 + -3

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Answer:

Area is A≈282.8 cm

Step-by-step explanation:

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2 years ago

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