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grandymaker [24]
3 years ago
9

Help me!! solve for d

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

d =±2sqrt(7) i

Step-by-step explanation:

d^2 = -28

Take the square root of each side

sqrt(d^2) = ±sqrt(-28)

d = ±sqrt(-28)

d = ±sqrt(-1)sqrt(28)

We know that sqrt(-1) = i

d =±i*sqrt(4)sqrt(7)

d =±i 2sqrt(7)

d =±2sqrt(7) i

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5. From 13 friends to 14 friends
LUCKY_DIMON [66]

Answer:

That would be 1

Step-by-step explanation:

To get 13 out of 14 you must add 1.

7 0
2 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

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It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

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4 0
3 years ago
Part A: Marguerite rented a truck at $125 for 2 days. If she rents the same truck for 5 days, she has to pay a total rent of $27
kobusy [5.1K]

Answer:

y = 50x+25

f(x) = 50x+25

Step-by-step explanation:

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2 days

125 = 2x+b

5 days

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Subtract

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---------------------

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Divide by 3

150/3 = 3x/3

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y = 50x +b

Using the data for 2 days

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125 = 100 +b

125-100 = b

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The equation is y = 50x+25

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To graph, The x axis is number of days and the y axis is total cost

The number of days starts with 0, which is the y intercept

Let x = 0, y =25

Using the slope, we go 50 up and 1 to the right ( 50 dollars per day)

The next point plotted ins ( 1,50)

Draw a straight line

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3 years ago
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Answer:

Step-by-step explanation:

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still need help with this question?

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