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2 years ago

Round 593,204 to the nearest million

1 answer:

6 0

1,000,000 If the number is 5-9 (in this case, the one in the hundred-thousands place), you round up. If lower, then round down

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the length of each side of a square is 3 in. more than the length of each side of a smaller square. the sum of the areas is 45 i

Marat540 [252]

Answer:

2025 is the answer

Step-by-step explanation:

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2 years ago

Which number sentence has a difference of 5? 8-(-3) 0 -3-8 -3-(-8) 3-(-8)

valina [46]

Answer:

The 4th one

Step-by-step explanation:

-3-(-8)=5

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2 years ago

Simplify sin^2y/sec^2 y−1 to a single trigonometric function

liubo4ka [24]

Answer:

$\frac{ { \sin}^{2} y}{ { \sec}^{2}y - 1 } = { \cos }^{2} y$

Step-by-step explanation:

We know that ${ \tan }^{2} y = { \sec }^{2} y - 1$

Also , ${ \tan}^{2} y = \frac{ { \sin }^{2} y}{ { \cos }^{2}y }$

So ,

$\frac{ { \sin }^{2}y }{ { \sec }^{2}y - 1 } = \frac{ { \sin}^{2} y}{ { \tan }^{2} y} = \frac{ { \sin }^{2}y }{ \frac{ { \sin}^{2} y}{ { \cos}^{2}y } } = { \cos }^{2} y$

6 0

2 years ago

The least common multiple of the numbers 15, 12, 8

Ymorist [56]

Answer: LCM of 8, 12, and 15 is 120.

Step-by-step explanation:

I hope this helps!

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2 years ago

Read 2 more answers

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

$\cos(x)=-\frac{\sqrt{2}}{2}$ .

This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .

Answer is $\frac{3\pi}{4}$ .

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2 years ago