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4 years ago

HELP WILL MARK BRAINLIEST!!

Mathematics

1 answer:

Kay [80]4 years ago

5 0

Answer:

A jar contains 5 red, 4 blue, and 3 yellow marbles.

The probability of pulling a red marble, then pulling a blue marble, without replacement would be:

P = 5/(5+4+3) x 4/(5+4+3-1) = 5/12 x 4/11 = 0.15 = ~0.2

Hope this helps!

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I really need help solving please.

Alja [10]

Easy peasy
sub -4 for every x
f(-4)=3(-4)-5
f(-4)=-12-5
f(-4)=-17

answer is C

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3 years ago

Graphs can be used to estimate information not represented on the graph. True or False

Verizon [17]

I believe that it is true.

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3 years ago

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BEST ANSWER GET BRAINLIEST!!!! HELP PLEASE<br> 3^4 + 2 ⋅ 5 = ____. (Input whole numbers only.)

kherson [118]

3^4 = 3 * 3 * 3 * 3 = 81

<span>2 ⋅ 5 = 10

81 + 10 = 91

The answer is 91.</span>

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3 years ago

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Two sides of a triangle measure 25 cm and

julia-pushkina [17]

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4 years ago

A piece of wire of length 5050 is cut, and the resulting two pieces are formed to make a circle and a square. Where should the

algol [13]

Answer:

x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

Step-by-step explanation:

Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.

A circle with perimeter of x would have a radius of x/(2π), and its area would be

$A_c = \pir^2 = \pi (\frac{x}{2pi})^2 = \frac{x^2}{4\pi}$

A square with perimeter of 5050 - x would have side length of (5050 - x)/4, and its area would be

$A_s = (\frac{5050 - x}{4})^2 = \frac{(5050 - x)^2}{16}$

The total combined area of the square and circles is

$\sum A = A_c + A_s = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$

To find the maximum and minimum of this, we just take the 1st derivative, and set it to 0

$A' = \frac{2x}{4\pi} + \frac{-2(5050-x)}{16} = 0$

$\frac{x}{2\pi} - \frac{5050 - x}{8} = 0$

Multiple both sides by 8π and we have

$4x - 5050\pi + x\pi = 0$

$x(4 + \pi) = 5050\pi$

$x = \frac{5050\pi}{4 + \pi} = 2221.5$

At x = 2221.5:

$A = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$ = 392720 + 500026 = 892746 [/tex]

At x = 0, $A = 5050^2/16 = 1593906$

At x = 5050, $A = \frac{5050^2}{4\pi} = 2029424$

As 892746 < 1593906 < 2029424, x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

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3 years ago