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3 years ago

what percent was the first increase in population for the gold rush in California? a 100% b 200% c 500% d 1000%

Mathematics

1 answer:

nadya68 [22]3 years ago

3 0

I think it was 500% because it started with 2000 non natives and then went to 15000.

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Find the inequality represented by the graph. Thanks!<br><br> (plz no spam...)

nikitadnepr [17]

Answer:

y > (1/3)x - 3.

Step-by-step explanation:

The graph of a line can be written in y = mx + b form where b is the y-intercept and m is the slope.

In the image, the slope of the graph from the given points is 1/3.

In the image, the y-intercept is -3.

Therefore, the line is y = (1/3)x -3. However, we aren’t done yet! This is an inequality, not an equation!

We see the line isn’t dotted, so that means it must be > or <.

We substitute the point (0,0) into the line equation we got and find that 0 > (1/3)(0) - 3 = -3. Since (0,0) is part of the inequality, we have that y > (1/3)x - 3.

I hope this helps! :)

6 0

3 years ago

Read 2 more answers

Sides or angles with the same measure are congruent. True or false

ololo11 [35]

Answer:

True

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What is 4 divided by 2 3/4. for 6th grade math

Goshia [24]

Answer:

3 1/3

Step-by-step explanation:

4/(2 3/4)

4/(6/4)

4÷6/4

4*4/6

20/6

3 2/6 =3 1/3

8 0

3 years ago

Susan started her homework at 1{:}59\text { p.M.}1:59 p.M.1, colon, 59, start text, space, p, point, m, point, end text and fini

inn [45]

Answer:

Step-by-step explanation:

Susan started her homework at = 1:59 pm

She took time = 96 mins

Time at which she had volleyball practice = 4:00 pm

So, time between her starting of homework and starting of volleyball is given by

1:59 pm to 4:00 pm = 2 hrs and 1 mins

2 hr 1 min = 120 mins + 1 min = 121 mins

But she took 96 mins to do her homework, so

Out of 121 mins, 96 mins she took for homework

Remaining time = 121 mins - 96 mins = 25 mins

Therefore, time Susan had between finishing her homework and the beginning of volleyball practice is 25 mins

7 0

3 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

3 years ago