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solniwko [45]
3 years ago
15

Two cylinders are shown below which cylinder has a greater volume use 3.14 for pi

Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer:

Cylinder Q has a greater volume

Step-by-step explanation:

For this question we need to utilise the volume of a cylinder which is

→ Volume of a cylinder = π × r² × h

Let's substitute in the values and then do the analysis

<u>Cylinder P</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 4.25² × 14

⇒ Simplify

→ Volume of a cylinder = 794.430242277

<em>The volume of cylinder P is 794.430242277</em>

<em>-------------------------------------------------------------------------------------------------------</em>

<u>Cylinder Q</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 7² × 8.5

⇒ Simplify

→ Volume of a cylinder = 1308.47334022

<em>The volume of cylinder Q is 1308.47334022</em>

<em>-------------------------------------------------------------------------------------------------------</em>

We can see that cylinder Q has a greater volume

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Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

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.

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Answer:

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Finally divide  both sides by 2 and your final answer is -3 = x

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