Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
$48.60
Step-by-step explanation:
4 7/5 is a funny way to express a fraction... but anway..... if this is correct, then the answer is as follows:
5/6 kg ------> cost $7.50
1 kg ----> costs $7.50 ÷ 5/6 kg = $9
4 7/5 kg ------> costs $9 x (4 7/5) = $9 x (27/5) = $48.60
The length of that semi circle is 6pi. So the perimeter should be 6pi + 24
<span>8x + 8y = -48
-------------------------
Plug in -8 for x
(8) (-8) + 8y = -48
-------------------------------
Simplify
</span><span><span><span>(8) </span><span>(<span>−8</span>) </span></span>+ <span>8y </span></span>= <span>−<span>48
</span></span><span><span>−64 </span>+ <span>8y </span></span>= <span>−<span>48
</span></span><span><span>8y </span>− 64 </span>= <span>−<span>48
</span></span>-----------------------------------------
Add 64 to each side
<span><span><span>8y </span>− 64 </span>+ 64 </span>= <span><span>−48 </span>+ 64
</span><span>8y </span>= <span>16
</span>---------------------------------------------------
Finally, divide each side by 8
8y ÷ 8 = 16 ÷ 8
y = <span>2
</span>----------------------------------------------------------------
y = 2 is your answer
Solve for n
Simply both sides 11(n-1)+35=3n
Distribute (11)(n) + (11)(-1) + 35 = 3n
11n+-11+35=3n
Combine like terms (11n)+(-11+35)=3n
11n + 24 =3n
Subtract 3n from both sides
11n+24-3n=3n-3n
8n + 24 = 0
Subtract 24 from both sides
8n+24-24=0-24
8n = -24
Divide both sides by 8
8n = -24
8 8
n = -3
