Find the value of the expression m − 4.6 for m = 7.

levacccp [35]

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7 0

3 years ago

A gardener has a circular flower bed with a radius of 17 feet. If she wants to make a square flower bed with the same area as th

mylen [45]

We know that

• The radius is 17 feet.

First, we find the circular area

$\begin{gathered} A=\pi(r)^2 \\ A=3.14(14)^2\approx3.14\cdot196\approx615.44ft^2 \end{gathered}$

This means the square flower bed will have an area of 615.44 square feet. So, we find its sides with the formula for squared areas

$\begin{gathered} A=l^2 \\ 615.44=l^2 \\ l=\sqrt{615.44}\approx24.808 \end{gathered}$ <h2>Therefore, the bed should have sides of 24.808 feet, approximately.</h2>

8 0

11 months ago

Suppose that m∠A = m∠D. Which other fact would guarantee that the triangles are SIMILAR?

zhenek [66]

B) m∠C = m∠F
Because now m∠B = m∠E because of the 180 total rule, and if all 3 ∠s are = then they are similar

8 0

3 years ago

Read 2 more answers

A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has

ExtremeBDS [4]

Answer:

$t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781$

$p_v =P(t_{(23)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=136$ represent the sample mean

$s=11$ represent the sample standard deviation

$n=24$ sample size

$\mu_o =140$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:

Null hypothesis: $\mu \geq 140$

Alternative hypothesis: $\mu < 140$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=24-1=23$

Since is a one left tailed test the p value would be:

$p_v =P(t_{(23)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.

4 0

3 years ago

En un entrenamiento, Mariana metió 12 de los 15 tiros al arco que pateo. Carla tuvo una efectividad del 75%. Cual de las dos chi

Lady bird [3.3K]

Answer:

Mariana has better performance.

Step-by-step explanation:

We are given that in a training session, Mariana made 12 of the 15 shots on goal that she kicked and Carla had an effectiveness of 75%.

And we have to find which girl's performance is better.

Since it is stated that Carla had an effectiveness of 75%.

Similarly, we will find the effectiveness of Mariana;

Total shots available to Mariana = 15 shots

Number of shots on goal = 12

So, her effectiveness = $\frac{12}{15} \times 100$

= $4 \times 20$ = 80%

This shows that Mariana has a better performance as compared to Carla as 80% > 75%.

4 0

3 years ago