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NeTakaya
2 years ago
7

Find the value of the expression m − 4.6 for m = 7.

Mathematics
1 answer:
stich3 [128]2 years ago
3 0

Answer:

2.4

Step-by-step explanation:

If you replace m with 7, the expression is now 7-4.6.

7-4.6=2.4

The value of the expression is 2.4.

-hope it helps

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5/6, 1/4, and 2/3 yard. Needs 1 yd of cable
mixer [17]
1. So first of all we have to divide the 3 fractions into decimals to get a decimal to compare. So 5/6 is the same as 5 divided by 6 which is .83 bar and so on...

5/6= .83 bar
1/4= .25
2/3= .66 bar

So 5/6 and 2/3 are closer to one.




2. The two shortest pieces are 2/3 and 1/4 so you se 1/4 + 2/3. Let’s get a common denominator for these fractions. The common denominator is 12. So multiply 1/4 • 3 to get 3/12 and multiply 2/3 by • 4 to get 8/12. Add them together and you get 11/12. So he would need 1/12 more cable or 0.083 bar.


3. Now we have to find a common denominator for all of them. The common denominator is 12 again. Multiply 5/6•2 and then you get 10/12, then add 10/12 +2/12(from 1/4) and then you get leftover with 9/12 or 3/4 more wire.
3 0
2 years ago
If I had $33,50 last month and this month I got a raise and brought back $45,70 how much more did I bring back
Effectus [21]

You brought back 12.2

hope that helped

5 0
3 years ago
Giving 15 points for the answer.
max2010maxim [7]

Answer:

4p-3

Explaination

when we subtract

4p-3 -3p-6

it will give us p _9

8 0
1 year ago
-2/5x - 1/2 + x = -40/11
IgorLugansk [536]

Answer: x = 6.56

Step-by-step explanation: -0.4x - 0.5 + x = 3.63

-0.4x^2 - 0.5 = 3.63

-0.4x^2 = 4.13

0.63x = 4.13

x = 6.56

7 0
2 years ago
Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha
kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable X follows a Poisson distributionP(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda

Evaluate the formula at k=2,3:

P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}

#since

4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda

The mean and variance of the Poisson distributed random variable is equal to \lambda:

\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75

#By property variance:

\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125

The expectation is 1.3125

4 0
3 years ago
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