Answer:
final concentration: Ca = 0.014 M
Explanation:
Velocity of reaction:
∴ α: order of reaction, assuming α = 1
∴ K = 0.249 s-1.......rate constant
∴ Cao = 0.050 M......initial concentration
∴ t = 5 s.......reaction time
⇒ δCa/δt = K*Ca
⇒ ∫δCa/Ca = K*∫δt
⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245
⇒ Cao/Ca = 3.473
⇒ Ca = 0.050/3.473
⇒ Ca = 0.014 M
Answer:
The answer to your question is below
Explanation:
1)
Balanced chemical reaction
2CH₃OH + 3O₂ ⇒ 2 CO₂ + 4H₂O
Reactant Element Product
2 C 2
8 H 8
8 O 8
Molar mass of CH₃OH = 2[12 + 16 + 4]
= 2[32]
= 64 g
Molar mass of O₂ = 3[16 x 2] = 96 g
Theoretical proportion CH₃OH/O₂ = 64 g/96g = 0.67
Experimental proportion CH₃OH/O₂ = 60/48 = 1.25
Conclusion
The limiting reactant is O₂ because the Experimental proportion was higher than the theoretical proportion
2)
Balanced chemical reaction
S₈ + 12O₂ ⇒ 8SO₃
Reactant Elements Products
8 S 8
24 O 24
Molar mass of S₈ = 32 x 8 = 256 g
Molar mass of O₂ = 12 x 32 = 384 g
Theoretical proportion S₈ / O₂ = 256 / 384
= 0.67
Experimental proportion S₈ / O₂ = 40 / 35
= 1.14
Conclusion
The limiting reactant is O₂ because the experimental proportion was lower than the theoretical proportion.
Answer:
Ionic
Explanation:
Lithium is an alkali metal and form an ionic bond by donating an electron.
Fluorine is a halogen and forms ionic bonds by accepting an electron.
The electronegativity difference between lithium (0.98) and fluorine (3.98) is 3 Pauling units. Usually, when elements have a difference of 1.7 (or 2.0) Pauling units the bond is classified as ionic.
Hope this helps! If you have any more questions or need more explanation please leave a comment down below and I will reply ASAP. Good luck!
Selectively Permeable means that some things can move across the cell membrane while others cannot.
Here is a sentence: Because of the selectively permeable membrane, the germs were kept out while the food went in.
Answer: There are 4 monofluoro derivatives of methylcyclopentane. Only 1 derivative has flourine atom attached to a primary carbon.
Explanation: The compound methylcyclopentane has 1-primary carbon, 4- secondary carbons and 1-tertiary carbon.
1) Primary carbon (1°): In this the carbon atom is attached directly to only one carbon atom.
2) Secondary carbon (2°): In this the carbon is attached directly to two carbon atoms.
3) Tertiary Carbon (3°): In this the carbon is attached directly to three carbon atoms.
The monofluoro derivatives are shown in the image below.
Structure B is the only derivative which has fluorine attached to primary carbon atom.
