Question

Help pure people pls

Answer 1

Answer:

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

                      = $\sqrt{(3-1)^2+(5-3)^2}$

                      = $\sqrt{8}$

                      = 2.83 units

Length of AD = $\sqrt{(3-5)^2+(5-3)^2}$

                      = $\sqrt{8}$

                      = 2.83 units

Length of BC = $\sqrt{(1-3)^2+(3+1)^2}$

                      = $\sqrt{20}$

                      = 4.47 units

Length of DC = $\sqrt{(5-3)^2+(3+1)^2}$

                       = $\sqrt{20}$

                       = 4.47 units

Perimeter of the quadrilateral = AB + AD + DC + BC

                                                 = 2.83 + 2.83 + 4.47 + 4.47

                                                = 14.6 units  

Option (B) is the answer.