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Vika [28.1K]
3 years ago
10

MARKING BRAINLIEST it’s not 5/7

Mathematics
1 answer:
OLEGan [10]3 years ago
6 0

Answer: 3/7

Step-by-step explanation:

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How to do s=3F-24 solve the formula fo f and plzz show how you got it
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Fine the value of x in the triangle. Then classify the triangle as acute, right, or obtuse. 83, obtuse 88, acute 87, obtuse 98,
nika2105 [10]

Answer:

x=88, so it is acute.

Step-by-step explanation:

The two known angles are 45 degrees and 47 degrees. We know that in a triangle, the three angles always add up to 180 degrees.

This means that the third angle is 180-(45+47), or 180-92, or 88. So, the third angle is 88 degrees.

Acute triangles are when all the angles are less than 90. Right is when one angle is exactly 90. Obtuse is when one is more than 90. 88, 45, and 47 are all less than 90, so it is an acute triangle.

3 0
3 years ago
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Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30
TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

-7, -3, 1, 5, . . .

An arithmetic sequence has a constant difference d and is defined by

a_n=a_1+\left(n-1\right)d

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4

\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

d=4

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=-7

as

a_n=a_1+\left(n-1\right)d

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=4\left(n-1\right)-7           ∵ d=4

\mathrm{Arithmetic\:sequence\:sum\:formula:}

n\left(a_1+\frac{d\left(n-1\right)}{2}\right)

\mathrm{Plug\:in\:the\:values:}

n=30,\:\space a_1=-7,\:\spaced=4

=30\left(-7+\frac{4\left(30-1\right)}{2}\right)

=30\left(58-7\right)     ∵  \frac{4\left(30-1\right)}{2}=58

=30\cdot \:51

=1530           ∵  \mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

a_n=4\left(n-1\right)-7

n = 30

\sum _{n=1}^{30}\:4\left(n-1\right)-7

=\sum _{n=1}^{30}4n-11

\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n

=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11

as

\sum _{n=1}^{30}4n=1860

and

\sum _{n=1}^{30}11=330

so

=1860-330

=1530

7 0
4 years ago
the pattern continues, what would be the eighth number in the pattern?4. 25, 28, 32, 37, 43 ______ PLS HELP ME
fredd [130]

25,28,32,37,43,50,58,67.

\boxed{The\:eighth\:number\:in\:the\:pattern\:is\:67.}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

25, 28, 32, 37, 43,50,58,67\\ ✒ \: 25 + 3 = 28 \\ ✒ \: 28 + 4 = 32 \\ ✒ \: 32 + 5 = 37 \\ ✒ \: 37 + 6 = 43 \\ ✒ \: 43 + 7 = 50 \\ ✒ \: 50 + 8 = 58 \\ ✒ \: 58 + 9 = 67

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}

4 0
3 years ago
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