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Marta_Voda [28]
3 years ago
12

Translate the sentence into an equation.

Mathematics
1 answer:
9966 [12]3 years ago
5 0

Answer:

4c + 6 = 9

I hope this helps

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Consider the image of EFGH for the translation (x, y) → (x – 3, y + 1). What is the ordered pair of F′?
omeli [17]

Answer:

F'(-1,3)

Step-by-step explanation:

The rule for the translation is given as

(x,y)\rightarrow (x-3,y+1)

The coordinates of F are (2,2).

We substitute these coordinates into the translation rule to find the coordinates of F'.

F(2,2)\rightarrow F'(2-3,2+1)

F(2,2)\rightarrow F'(-1,3)

3 0
3 years ago
PLEASE HELP URGENT WILL GIVE BRAINLIEST
Vadim26 [7]
The answer is 2.3716 have a great day y’all
4 0
2 years ago
Given g(x)=-x^2+10x-3 <br> Find g(-3)
inn [45]
Sub g to (-3) and then solve from there using PMDAS and equation solving skills, Photomath is a fantastic resource
8 0
3 years ago
The bakers at healthy BAKERY can make 360 bagels in 10 hours. how many bagels can they bake in 13 hours? what was that rate per
babunello [35]
The rate per hour is equal to the total bagels made divided by the time to make them.
360 ÷ 10 = 36
If for 1 hour they make 36 bagels, for 13 hours they can bake
36 x 13 = 468 bagels.
7 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
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