Answer:
Train A is faster by a factor of 1.01
Step-by-step explanation:
Given:
Train A:
Distance = 175 Miles
Time = 4 Hours
Train B:
y=43.5x
To Find:
which train travels at a faster rate in by what factor =?
Solution:
The speed of the train A = 
The speed of train A =
The speed of train A = 43.75 miles per hour
Speed of the train B is the slope of the given line
The standard equation of the slope of the line is
y = mx+b
where m is the slope
and we are given with
y = 43.5x
So comparing with the standard equation
m = 43.5
Hence the speed of train B is 43.5 miles per hours
Train A travels faster
rate =1.01
12 because if u had 3 groups of 4 that would be 3+3+3+3
The cubic function is f(x) = x^3
You need to perform three transformations to the cubic function to obtain
f(x) = - (x + 2)^3 - 5.
Those transfformations are:
1) Shift f(x) = x^3, 2 units leftward to obtain f(x) = (x + 2)^3
2) reflect f(x) = (x + 2)^3 across the x-axis to obtain f(x) = - (x + 2)^3
3) shift f(x) = - ( x + 2) ^3, 5 units downward to obtain f(x) = - (x + 2)^3 - 5
Start with the second expression. That factors easily into (8x-3)(8x+3).
Since 64x^2 + 48x + 9 has no negative signs, I'd bet that the common factor is (8x+3). Divide <span>64x^2 + 48x + 9 by that to verify.
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Step-by-step explanation:
Given
