Answer:
9:49 is the answer because question say ratio is square of small and big
We could find the slope with this formula
m = (y₂ - y₁)/(x₂ - x₁)
with (x₁,y₁) and (x₂,y₂) are the points that is located on the line.
NUMBER 20
Given:
(x₁,y₁) = (-2,3)
(x₂,y₂) = (7,-4)
Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (-4 - 3) / (7 - (-2))
m = -7 / (7+2)
m = -7/9
The slope of the line is -7/9
NUMBER 21
Given:
(x₁,y₁) = (-6,-1)
(x₂,y₂) = (4,1)
Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1-(-1)) / (4 -(-6))
m = (1+1) / (4+6)
m = 2/10
m = 1/5
The slope of the line is 1/5
NUMBER 22
Given:
(x₁,y₁) = (-9,3)
(x₂,y₂) = (2,1)
Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1 - 3) / (2 - (-9))
m = -2 / (2 + 9)
m = -2/11
The slope of the line is -2/11
Answer:
- amberjack, 21 lbs
- kingfish, 42 lbs
- white marlin, 84 lbs
- tarpon, 105 lbs
Step-by-step explanation:
Let k, a, m, t represent the weights of the kingfish, amberjack, marlin, and tarpon, respectively. The problem statement tells us ...
- k = 2a
- m = 2k
- t = 5a
- k + a + m + t = 252
Using substitution, we can rewrite the last equation as ...
... (2a) + (a) + 2(2a) + (5a) = 252
... 12a = 252 . . . . . collect terms
... a = 21 . . . . . . . . .divide by 12
Then k = 2a = 42; m = 2k = 84; t = 5a = 105.
2 | 1 3 3 -3 6
| 0 2 10 26 46
___________
1 5 13 23 52
x^3+5x^2+13x+23+ (52/(x-2))
The slant height, x, is 7.5 mm because you use the pythagorean formula and solve for c, since the you're solving for the hypotenuse which is the longest side.
