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3 years ago

Ujalakhan01! Please help me! ASAP ONLY UJALAKHAN01. What's (x-1)(x-1)?

Mathematics

2 answers:

algol [13]3 years ago

6 0

Answer:

$\boxed{x^2-2x+1}$

Step-by-step explanation:

$(x-1)(x-1)$

Apply FOIL Method.

$x(x-1)-1(x-1)$

$x^2-x-x+1$

Combine like terms.

$x^2-2x+1$

Sauron [17]3 years ago

3 0

Answer:

$x^2-2x+1$

Step-by-step explanation:

=> (x-1)(x-1)

Using FOIL

=> $x^2-x-x+1$

=> $x^2-2x+1$

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PLEASE HELP If the volume of a box is 500 cubic meters, the height is 2 1/2 meters and the length is 20 inches, what is the heig

Ede4ka [16]

Answer:

The height is 10

Step-by-step explanation:

500 ÷ 2 1/2 ÷ 20 = H

25 ÷ 2 1/2 = H

H = 10

6 0

2 years ago

Please Help with problems 7-10!!!!

Ahat [919]

Answer:

7) 3m + 21

8) 8t + 12

9) 45 + 30r

10) 32n - 16n or just 16n

Step-by-step explanation:

just use the distributive property

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5 0

2 years ago

Please help me ASAP !!

Nadya [2.5K]

Answer:

Step-by-step explanation:

<1+<2=90 complementary

<1=4 times <2

X+4x=90

5x=90

X=18

<1=18×4=72 degrees

<2=18 degrees

<1=<3 because they are vertical

Do <3= 72

<3+<4=180 because they are supplementary

72+<4=180

<4=108 degrees

<3=72 degrees

4 0

3 years ago

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

5 0

3 years ago

Abel and Cedric will share a total of $180. Abel will receive half as much as Cedric. What amount. in dollars, will Cedric recei

babymother [125]

Answer:

Abel receives $60, and Cedric receives $120

Step-by-step explanation:

Let Abel's share = A

Let Cedric's share = C

we are given the following

A + C = 180 - - - - - (1) (Abel and Cedric will share a total of $180)

$A = \frac{C}{2}\ - - - - - - - (2)$ (Abel will receive half as much as Cedric. )

from equation 2:

$A = \frac{C}{2}\\ C = 2A\ - - - - - - (3)$

putting this value of C in eqn (3) into eqn (1)

A + (2A) = 180

3A = 180

∴ A = 180 ÷ 3 = 60

to find C, let us replace the value of A in eqn (3) with 60

C = 2A - - - - (3)

C = 2 × 60

C = 120

Therefore, Abel receives $60, and Cedric receives $120

5 0

2 years ago