f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.
, written in vertex form is
, where (h, k) = (-1, -11)
Therefore, range ={y|y ≥ -11}
Answer:
The and is x-2)-2(x + 3)3=0
Answer:
8j - 
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Step-by-step explanation:
hope this helps! :D
Answer:
hey I believe standard form would look like this: f(x) = a(x - h)^2 + k
this is regular form f(x)=ax^2+bx+c or something like x^2+4x+4.
I think H and K are the vertex
hope this is close to what your looking for.
Step-by-step explanation:
I think it's x^2+6x-18
