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Alexus [3.1K]
4 years ago
6

Help me please algebra 2

Mathematics
2 answers:
Deffense [45]4 years ago
7 0
-4 is not a whole number since whole numbers have to be positive.
jeka944 years ago
5 0
By definition, whole numbers will never be negative.  They are the numbers we count with but include 0.  -4 is not a whole number.
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Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)
Elan Coil [88]

Answer:

10u^{3}+4u^{2}-2u+10 or 2(5u^{3}+2u^{2}-u+5)

Step-by-step explanation:

we have

(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)

step 1

Group terms that contain the same variable

(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)

step 2

Combine like terms

(10u^{3})+(4u^{2})+(-2u)+(10)

step 3

Eliminate parenthesis

10u^{3}+4u^{2}-2u+10

step 4

Factor the number 2

2(5u^{3}+2u^{2}-u+5)

8 0
3 years ago
Read 2 more answers
Let f be the function defined as follows.
Debora [2.8K]
Y = f(x) = 8x^2 - 2x + 3
a.) dy/dx = 16x - 2

b.) dy = (16x - 2)dx
dy = (16(2) - 2)(2 - 1.97) = 0.03(32 - 2) = 0.03 * 30 = 0.9
dy = 0.9

c.) (8(2)^2 - 2(2) + 3) - (8(1.97)^2 - 2(1.97) + 3) = 31 - 30.1072 = 0.8928
Δy = 0.8928
4 0
4 years ago
Please help me with this I need the answers please
brilliants [131]

i think this is the answer

4 0
2 years ago
Write the standard form of an equation of an ellipse subject to the given conditions.
irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

\frac{x^2}{1369}+ \frac{y^2}{1394} =1

6 0
3 years ago
There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g
marissa [1.9K]

Answer:

10  buses are needed.

9  buses will only be able to take 468 people.

Explanation:

There are  461  +  20  =  481  people altogether needing transport.  Each bus can take at most 52 people.  The number of buses needed =   482  ÷  52. 482  ÷  52  =  9.25  buses.  You might be tempted to round down to 9 buses (because of the 2 that follows the decimal)  However, if there are 9 buses,   9  ×  52  =  468  people can be taken  There will still be   13  people to be transported.  This is an example of where you need to round UP to the next whole number.   10  buses are needed.  In reality it means that not all the buses will be full, but 10 buses are needed to ensure that everyone gets a ride to the museum.

7 0
4 years ago
Read 2 more answers
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