4)
Non linear:
y = 6 -x^2
y = 2x^2 + 2
y = x^3
5)
Rate of change is also the slope
= (72 - 69) / (51 - 48)
= 3/3
= 1
Rate of change = 1
6)
First you need to find slope
(3,0) and (5,2)
Slope = (2 - 0)/(5-3) =2/2 = 1
Equation
y - 0 = 1(x - 3)
y = x - 3
Answer:
Tyler's function is correct as y = x - 3, it matched the above.
Answer:
D. p + q = 7
Step-by-step explanation:
The slope of AB is ...
mAB = (y2 -y1)/(x2 -x1) = (1 -4)/(6 -p) = -3/(6 -p)
The slope of BC is ...
mBC = (q -1)/(9 -6) = (q -1)/3
We want the product of these slopes to be -1:
mAB·mBC = -1 = (-3/(6 -p))·((q -1)/3)
-(q-1)/(6 -p) = -1 . . . . cancel factors of 3
q -1 = 6 -p . . . . . multiply by -(6 -p)
q + p = 7 . . . . . matches choice D
Answer: 19 + (-27)
Step-by-step explanation:
Answer:
The answer is 8.30
Step-by-step explanation:
Using cos 41 = x/11
x = cos 41 × 11
x = 8.30
The 2nd option is the answer :)!
