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Step2247 [10]
4 years ago
12

What are the solutions to cos 2x = - 1​

Mathematics
1 answer:
N76 [4]4 years ago
4 0

Answer:

X can be - 1/2 or 0.5

2x0.5=-1

Step-by-step explanation:

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Solve<br>3 tan 8 &lt;-1 for 0 5 0521.​
BlackZzzverrR [31]

Answer:

Substitute the given value into the function and evaluate.

Substitute the given value into the function and evaluate.

3  tan  ( 8 )  <  −  1  =  0.4216225  <  −  1

0  =  0.4216225  <  −  1

5  =  0.4216225  <  −  1

521  =  0.4216225  <  −  1

Step-by-step explanation:

3 0
3 years ago
If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f
nikklg [1K]

The quadratic function given by:


f(x)=a(x-h)^2+k, \ \ \ a\neq 0


is in vertex form. The graph of f is a parabola whose axis is the vertical line x=h and whose vertex is the point (h, k). So:


To translate the graph of a function to the right, left, upward or downward we have:

For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)


By knowing this things, we can solve our problem as follows:


FIRST.

  • Translating <em>11 units to the left:</em>

g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2


  • Then translating<em> 5 units down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5


Since the new function is fatter, the factor we need to multiply the term (x+11)^2 <em>must be</em> less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.


<em>Therefore, the right answer is </em><em>b. f(x) = 1/2(x + 11)^2 - 5</em>


SECOND.

  • Translating <em>8 units to the right:</em>

g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2


  • Then translating<em> 1 unit down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1


As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.


<em>Therefore, the right answer is </em><em>a. g(x) = 1/3(x - 8)^2 - 1</em>

7 0
3 years ago
Help me plz !!!!!!!!!!!!!!!
seropon [69]

Answer:

A. 2/3 book/hour

Step-by-step explanation:

rewrite the fractions as a decimal if it can make it easier for you (0.5 book/0.75 hours) then divide which is 2/3 book/hour

8 0
3 years ago
A certain component is critical to the operation of an electrical system and must be replaced immediately upon failure. If the m
nekit [7.7K]

Answer:

Step-by-step explanation:

From the given information:

Assuming we have an integer c to represent the components in the stocks.

Thus, the needed probability can be expressed as:

P(X_1+X_2+ ........ X_c \ge 2000)

To break this down, we have:

P(\sum X_i \ge 2000) = P \Bigg(\dfrac{\sum X_i - 100n}{\sqrt{n \ Var (X)}} \ge \dfrac{2000-100 n }{\sqrt{n \times 900}} \Bigg )

P \Bigg(\dfrac{\sum X_i - 100n}{\sqrt{n \ Var (X)}} \ge \dfrac{2000-100 n }{\sqrt{n \times 900}} \Bigg )= P (Z \ge 0.95 ) \ \ \  because  \ Z_{0.05} = -1.65 \\ \\  \\  \dfrac{2000-100 n }{\sqrt{n \times 900}} = -1.65 \\ \\ \\ \dfrac{100\  n-2000  }{\sqrt{900n}} = 1.65  \\ \\ 100 n -1.65 \sqrt{900 n }-2000 = 0

By solving the equation:

n = 23

Thus, relating to the needed condition; n ≥ 23

The needed number of the components that should be in stock should be  at least 23.

5 0
3 years ago
- + 106 = 315 cubic inches
WARRIOR [948]

Answer:585 cubic inch

Step-by-step explanation:

volume=15 x 10 x 3 + 9 x 3 x 5

Volume=450 + 135

Volume=585

8 0
4 years ago
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