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Step2247 [10]
3 years ago
12

What are the solutions to cos 2x = - 1​

Mathematics
1 answer:
N76 [4]3 years ago
4 0

Answer:

X can be - 1/2 or 0.5

2x0.5=-1

Step-by-step explanation:

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Does the relation {(-2,2), (-7,1), (-3,9), (-8,4), (-9,5), (-6,8)) represent
Gelneren [198K]

Answer:

Yes

Step-by-step explanation:

This does represent a function because every x-value only goes to one y-value.

7 0
2 years ago
Simplify C^5 x c<br> Plz can someone figure it out cuz I don’t get it
Fofino [41]

Answer:

c^6

Step-by-step explanation:

So, c is the same as c^ 1 ... therefore

c^5 x c

= c^5 x c^1

When we multiply two numbers with same base and different exponent, we add the exponents which in this case as 5 and 1

So c^5 x c^1

= c^(5+1)

= c^6

This is the simplest form

5 0
3 years ago
Read 2 more answers
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
ycow [4]

This  involves quite a lot of arithmetic to do manually.

The first thing you do is to make the first number in  row 2  = to 0.

This is done by R2 = -3/2 R1 + R2

so the matrix becomes

( 2        1          1)    ( -3 )

( 0    -13/2   3/2)   (1/2 )

(5       -1           2)  (-2)

Next step is to make  the 5 in row 5  = 0  

then  the -1  must become zero

You aim  for the form

( 1 0 0) (x)

(0 1 0) (y)

(0 0 1) ( z)

x , y and z will be the required solutions.


4 0
3 years ago
Read 2 more answers
the diameter of the sweep of the main rotor of the eh101 helicopter is 18.6 meters. A toy model of it has a sweep of 31 centimet
Aliun [14]

Answer:

The actual length of 60 cm is modeled as 1 cm length.

Step-by-step explanation:

The diameter of the sweep of the main rotor of the helicopter is 18.6 meters i.e. 1860 cm.

Now, the toy model of the helicopter has a sweep of 31 cm.

Therefore, the scale in which the model is made is 1860 : 31 i.e. 60 : 1 ratio.

So, the actual length of 60 cm is modeled as 1 cm length. (Answer)

4 0
3 years ago
Read 2 more answers
Pls help
solong [7]
Ok let’s solve it

5(x-2)^2-20=0

first let’s foil (x-2)

5(x^2-4x+4) -20=0

now distribute the 5

5x^2 -20x +20 -20 = 0

combine like terms

5x^2-20x=0

take the gcf

5x(x-4)=0

x=0, 4

solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k

7 0
3 years ago
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