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Step2247 [10]
3 years ago
12

What are the solutions to cos 2x = - 1​

Mathematics
1 answer:
N76 [4]3 years ago
4 0

Answer:

X can be - 1/2 or 0.5

2x0.5=-1

Step-by-step explanation:

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One ball is drawn from a bag containing 4 red balls numbered 1–4 and 10 white balls numbered 5–14. Find the following probabilit
omeli [17]

Step-by-step explanation:

9 in total numbers can't be divided by 3...

therefore your probability will be = 9/14

= 0.64

8 0
3 years ago
Which decimals are equivalent to 5x10 + 2x1/100
pishuonlain [190]

Answer:

50.2

Step-by-step explanation:

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1 year ago
Steve has 8 biscuits in a tin. There are 5 digestive and 3 chocolate biscuits. Steve takes two biscuits at random from the tin.
Fudgin [204]

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5/7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Use the given zero to find the remaining zeros of each function f(x)=2x^4+5x^3+5x^2+20x-12 zero:-2i
frutty [35]

Answer:

1/2, 3

Step-by-step explanation:

This is a pretty involved problem, so I'm going to start by laying out two facts that our going to help us get there.

  1. The Fundamental Theorem of Algebra tells us that any polynomial has <em>as many zeroes as its degree</em>. Our function f(x) has a degree of 4, so we'll have 4 zeroes. Also,
  2. Complex zeroes come in pairs. Specifically, they come in <em>conjugate pairs</em>. If -2i is a zero, 2i must be a zero, too. The "why" is beyond the scope of this response, but this result is called the "complex conjugate root theorem".

In 2., I mentioned that both -2i and 2i must be zeroes of f(x). This means that both x-2i and x+2i are factors of f(x), and furthermore, their product, x^2+4, is <em>also</em> a factor. To see what's left after we factor out that product, we can use polynomial long division to find that

2x^4+5x^3+5x^2+20x-12=(x^2+4)(2x^2+5x-3)

I'll go through to steps to factor that second expression below:

2x^2+5x-3=2x^2+6x-x-3\\=2x(x+3)-(x+3)\\=(2x-1)(x+3)

Solving both of the expressions when f(x) = 0 gets us our final two zeroes:

2x-1=0\\2x=1\\x=1/2

x+3=0\\x=-3

So, the remaining zeroes are 1/2 and 3.

8 0
3 years ago
Read 2 more answers
Solve the following equation for a. t=G/a+h
monitta

Answer:

t = G/(a + h)

t(a + h) = G

a + h = G/t

a = (G/t) - h

t = (G/a) + h

t - h = G/a

a(t - h) = G

a = G/(t - h)

8 0
2 years ago
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