For any function, we call x the ____________ value and y is the ______________

Illusion [34]

-12 + 20 = 8

then divide the answer by -4

8/(-4) = -2

when you divide a negative number, the answer will be the opposite sign of the numerator

-2 is your answer

hope this helps

7 0

2 years ago

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Can someone please help me to find the remainder when f(x) is divided by (x^2-4)?

yuradex [85]

Answer:

Step-by-step explanation: Given : f(x)=x

4

−3x

2

+4

f(2)=(2)

4

−3(2)

2

+4

=16−12+4=8

8 0

2 years ago

In the diagram below, KL = 12 and LM = 8. Which additional facts would guarantee that JKLM is a parallelogram? Check all that ap

salantis [7]

I don't know the last point, but I'm going to assume it's N.
MN = 12 and KN = 8.
That would make this a rectangle.
All angles add up to 360.

4 0

3 years ago

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Which set of ordered pairs does NOT represent a function?

saveliy_v [14]

I think it would be B but I'm not sure

3 0

2 years ago

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A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

2 years ago

For any function, we call x the ____________ value and y is the _______________ value.

For any function, we call x the value and y is the ___ value.