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astraxan [27]
2 years ago
6

For any function, we call x the ____________ value and y is the _______________ value.

Mathematics
1 answer:
Fantom [35]2 years ago
3 0
Numerator and denominator
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How to find variables of these #2 & #3
Lubov Fominskaja [6]
So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles  like  \bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
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\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}

now.. for 3) will be the second picture below


\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}

8 0
3 years ago
If the function rule is 5x, what is the value when x = 3?
cupoosta [38]
This means that we will plug 3 into our x values.

Our rule is 5x.

This means that:
5(3)

This means our final answer will be 15.
3 0
3 years ago
Need help must bring back to my school August 8
ivolga24 [154]

2: 4 is a factor and multiple of 8. 8 and 4 is also even numbers so is is most likely to be divisible by any number

4 0
3 years ago
Which diagram represents the postulate that states exactly one line exists between any two points?
Ivahew [28]

Answer:

C with points A and B on the line

5 0
3 years ago
Read 2 more answers
6
8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16     Eqn 1

8x+5y=113    Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

5x+5y=80    Eqn 3

Subtracting Eqn 3 from Eqn 2

(8x+5y)-(5x+5y)=113-80

8x+5y-5x-5y=33

3x=33

Dividing both sides by 3

\frac{3x}{3}=\frac{33}{3}\\x=11

Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

3 0
3 years ago
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