Two thirds.
1/3 +1/3 = 2/3.
You don’t add the denominator (bottom terms), you only add the numerators (the top terms)
Multiply dc over one on both sides on the left it’ll be cancelled out with a alone and on the right it would be b*dc - from a freshman
-5 and 15. -5 times 15 is equal to -75, and they also add to 10.
The probability of getting all heads is 1 / 2^6 = 1/64 as there is only 1 event where this happens in a possible 2^6 = 64 events. It is the same as the probability of getting all tails. The probability of getting at least 1 head is 1 - p(all tails) = 63/64.
Answer:
2n -4
Step-by-step explanation:
n+8 + n-12
Combine like terms
n+n+ 8-12
2n -4