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notka56 [123]
3 years ago
6

If f(x) = x + 4 and g(x) = x^2-1, what is (gºf)(x)?

Mathematics
2 answers:
aliina [53]3 years ago
8 0

Answer:

x^2+8x+15

Step-by-step explanation:

f(x)=x+4 \\\\g(x)=x^2-1 \\\\(g\circ f)(x)=(x+4)^2-1=\\\\x^2+8x+16-1=\\\\x^2+8x+15

Hope this helps!

Temka [501]3 years ago
8 0

Answer:

x² + 8x + 15

Step-by-step explanation:

(gºf)(x) = g((f(x)) = (x+4)² - 1 = x² + 8x + 16 - 1 = x² + 8x + 15

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\left\{\begin{array}{ccc}x-2y=16\\x-y=8\end{array}\right\\\\\#1\ elimination\ method:\\\left\{\begin{array}{ccc}x-2y=16\\x-y=8&|change\ signs\end{array}\right\\\underline{+\left\{\begin{array}{ccc}x-2y=16\\-x+y=-8\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ the\ equations\\.\ \ \ \ \ -y=8\to\boxed{y=-8}\\\\subtitute\ value\ of\ y=-8\ to\ the\ second\ equation\\\\x-(-8)=8\\x+8=8\ \ \ \ |subtract\ 8\ from\ both\ sides\\\boxed{x=0}\\\\Answer:\boxed{\boxed{\left\{\begin{array}{ccc}x=0\\y=-8\end{array}}}

\#\ subtitute\ method:\\\left\{\begin{array}{ccc}x-2y=16\\x-y=8&|add\ "y"\ to\ both\ sides\end{array}\right\\\left\{\begin{array}{ccc}x-2y=16&(1)\\x=y+8&(2)\end{array}\right\\\\subtitute\ (2)\ to\ (1)\\\\(y+8)-2y=16\\y+8-2y=16\\-y+8=16\ \ \ \ |subtract\ 8\ from\ both\ sides\\-y=8\to \boxed{y=-8}\\\\subtitute\ value\ of\ y=-8\ to\ (2)\\x=-8+8\\\boxed{x=0}\\\\Answer:\boxed{\boxed{\left\{\begin{array}{ccc}x=0\\y=-8\end{array}\right}}
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3 years ago
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