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2 years ago

Expression in expanded form for 3.339

Mathematics

1 answer:

Molodets [167]2 years ago

5 0

3 + 0.3 + 0.03 + 0.09 should be your answer

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The sum of an integer and 3 times the next consecutive integer is -21. Find the value of the greater integer.

Anni [7]

Answer: -5

Step-by-step explanation:

i=integer

i+3(i+1)=-21

i+3i+3=-21

4i+3=-21

4i=-24

i=-6

i+1=-6+1=-5

5 0

1 year ago

Round to the nearest integer 31.4829

Lady_Fox [76]

9514 1404 393

Answer:

Step-by-step explanation:

The fractional part of the given number is 0.4829, which is less than 0.5. That means the nearest integer is the integer below the given number:

8 0

3 years ago

Al can wash a car in 60 minutes, and bill can wash a car in 30 minutes. cathy can wash a car in 20 minutes. how long, in minutes

choli [55]

B) 36

To figure this out you need to average the numbers. To average them you add them all up and divide by how many are there.
(60+30+20)/3
(90+20)/3
110/3
36

3 0

3 years ago

[8] meaning. <br><br>what's the [ ] mean

kotykmax [81]

It changes it into negative

6 0

3 years ago

Chose parameters h and k such that the system has a) a unique solution, b) many solutions, and c) no solution. X1 + 3x2 = 4 2x1

AysviL [449]

Answer:

a) The system has a unique solution for $k\neq 6$ and any value of $h$ , and we say the system is consisted

b) The system has infinite solutions for $k=6$ and $h=8$

c) The system has no solution for $k=6$ and $h\neq 8$

Step-by-step explanation:

Since we need to base the solutions of the system on one of the independent terms ( $h$ ), the determinant method is not suitable and therefore we use the Gauss elimination method.

The first step is to write our system in the augmented matrix form:

$\left[\begin{array}{cc|c}1&3&4\\2&k&h\end{array}\right]$

The we can use the transformation $r_0\rightarrow r_0 -2r_1$ , obtaining:

$\left[\begin{array}{cc|c}1&3&4\\0&k-6&h-8\end{array}\right]$ .

Now we can start the analysis:

If $k\neq 6$ then, the system has a unique solution for any value of $k$ , meaning that the last row will transform back to the equation as:

$(k-6)x_2=h-8\\x_2=h-8/(k-6)$

from where we can see that only in the case of $k=6$ the value of $x_2$ can not be determined.

if $k=6$ and $h=8$ the system has infinite solutions: this is very simple to see by substituting these values in the equation resulting from the last row:

$(k-6)x_2=h-8\\0=0$ which means that the second equation is a linear combination of the first one. Therefore, we can solve the first equation to get $x_1$ as a function of $x_2$ o viceversa. Thus, $x_2$ ( $x_1$ ) is called a parameter since there are no constraints on what values they can take on.

if $k=6$ and $h\neq 8$ the system has no solution. Again by substituting in the equation resulting from the last row:

$(k-6)x_2=h-8\\0=h-8$ which is false for all values of $h\neq 8$ and since we have something that is not possible $(0\neq h-8,\ \forall \ h\neq 8)$ the system has no solution

6 0

3 years ago