Answer:
a) P(X∩Y) = 0.2
b)
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability
that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:

137 - 16X = Y
Since Lorraine is picking blackberries in her backyard at a rate of 15 berries per minute, and after 16 minutes of picking, there are still 137 blackberries left to pick, to determine an equation that models how many berries are left (y) after x minutes of picking, the following calculation must be performed:
137 - 16X = Y
Thus, for example, after 5 minutes the calculation would be as follows:
- 137 - 16 x 5 = Y
- 137 - 80 = Y
- 57 = Y
Learn more about maths in brainly.com/question/25989509
Answer:
c
Step-by-step explanation:
Answer:
Step-by-step explanation:
64
Answer:
I'm getting stuck by

Sorry I can't help you out, if you find the answer through FP lmk