The last step of an equation whose solutions are x=-10 and x=-5 is:
(x+10)(x+5)=0
We need to add some previous steps, which make the equation an absolute value equation.
A way to do this, is writing |(x+10)(x+5)|=0,
the only solutions are still x=-10 and x=-5
Answer: |(x+10)(x+5)|=0
A rational number that is not a integer can be a demical and a rational that is a integer can not be a demical and also can be a whole number and it's opposite.
Answer:
15
Step-by-step explanation:
Ok so first you need to know how to calculate the volume of a cylinder
I will put the formula here: V=πr2h
Since pi is equal to 3.14 as said in the problem we can simply divide 282.6 by pi, the radius and 2
That is equal to 282.6/3.14*3*2
A little calculation shows that, the answer is 15
Hope this helps :)
![\sf \red⇛ \green {3a + 1 = 16}](https://tex.z-dn.net/?f=%20%5Csf%20%5Cred%E2%87%9B%20%5Cgreen%20%7B3a%20%2B%201%20%3D%2016%7D)
Move the constant to the right-hand side and change its sign to minus sign since it is in plus
![\sf \red⇛ \green{3a = 16 - 1}](https://tex.z-dn.net/?f=%20%5Csf%20%5Cred%E2%87%9B%20%5Cgreen%7B3a%20%3D%2016%20-%201%7D)
Subtract the numbers
![\sf\red ⇛ \green{3a = 15}](https://tex.z-dn.net/?f=%20%20%5Csf%5Cred%20%E2%87%9B%20%5Cgreen%7B3a%20%3D%2015%7D)
Divide both sides of equation by 3
![\sf \red⇛ \green{a = 5}](https://tex.z-dn.net/?f=%20%5Csf%20%5Cred%E2%87%9B%20%5Cgreen%7Ba%20%3D%205%7D)
- On observing the above steps, Option B is correct!
- <em>First</em><em> </em><em>step</em><em> </em><em>is</em><em> </em><em>subtraction</em><em> </em><em>then</em><em> </em><em>division</em>