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Masteriza [31]
3 years ago
7

Order -1 2/3, 1- 3/8, -1 4/5, and -1 9/20

Mathematics
2 answers:
uysha [10]3 years ago
8 0
What are you asking
Elis [28]3 years ago
5 0
From least to greatest?
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frez [133]
81 because their is no 14,24,or112,but there are 2 81's.
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Suppose you adding 43 and 28 will you regroup ? Explain
WITCHER [35]
Yes because 8 is bigger than 3.
3 0
2 years ago
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2 to the Third power -(30÷5) +9
OLga [1]

Answer:

11

Step-by-step explanation:

2^3-(30/5)+9

First, you divide 30/5 because it is in parentheses and we are following this rule for order of operations:

P- parentheses

E- exponents

M- multiplication

D- division

A- addition

S- subtraction

so 30/5 = 6 and plugged in is:

2^3-(6)+9

Next, we do exponents:

2^3 = 2x2x2 = 8

plugged back in:

8-(6)+9

Now, we do the math from left to right so:

8-6=2

2+9=11

11 is your answer

8 0
3 years ago
Suppose that the walking step lengths of adult males are normally distributed with a mean of 2.5 feet and a standard deviation o
Mumz [18]

Answer:

0% probability that the mean of the sample taken is less than 2.2 feet.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 2.5 feet and a standard deviation of 0.2 feet.

This means that \mu = 2.5, \sigma = 0.2

Sample of 41

This means that n = 41, s = \frac{0.2}{\sqrt{41}}

Find the probability that the mean of the sample taken is less than 2.2 feet.

This is the p-value of Z when X = 2.2 So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2.2 - 2.5}{\frac{0.2}{\sqrt{41}}}

Z = -9.6

Z = -9.6 has a p-value of 0.

0% probability that the mean of the sample taken is less than 2.2 feet.

6 0
3 years ago
A family built a house and wanted to put down in their rectangular yard. The sod costs $0.32 per square foot plus 10 per square
sammy [17]

Answer:

The total cost of purchasing and laying sods in the rectangular yard is $2,146.67  

Step-by-step explanation:

We are given the following in the question:

Dimensions of rectangular yard:

Length = 50 feet

Width = 30 feet

Area of rectangular yard =

A = \text{Length}\times \text{Width}\\A = 50\times 30\\A  = 1500\text{ square feet}

Cost of sod = $0.32 per square foot

Total cost of sod =

C_1 = \text{Unit cost of sod}\times \text{Area of yard}\\C_1 = 0.32\times 1500\\C_1 = 480\$

Cost of laying sods = $10 per square yard

Total cost of laying sod =

C_2 = \text{Unit cost of laying sod}\times \text{Area of yard}\\\\\text{1 square yard}=\dfrac{1}{9}\text{Square foot}\\\\C_2 = 10\times \dfrac{1500}{9}\\\\C_2 = 1666.67\$

Total cost of purchasing and laying the sod =

C = C_1 + C_2\\C = 480 +1666.67\\C = \$2,146.67

Thus, the total cost of purchasing and laying sods in the rectangular yard is $2,146.67

3 0
2 years ago
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