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3 years ago

Using the slope formula, find the slope of the line through the points (0,0) and (5, 20)

Mathematics

1 answer:

Gemiola [76]3 years ago

8 0

Answer:

m = 4

Step-by-step explanation:

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A store owner received 18 cases of soda. Each case has 24 cans of soda. The owner sells each can for $0.60. Which number sentenc

Radda [10]

Answer:

Total money get from soda cans = $259.2

Step-by-step explanation:

Given:

Number of soda cases = 18

Number of soda can in each case = 24

Price of each soda can = $0.60

Find:

Total money get from soda cans

Computation:

Total money get from soda cans = Number of soda cases x Number of soda can in each case x Price of each soda can

Total money get from soda cans = 18 x 24 x 0.60

Total money get from soda cans = $259.2

8 0

3 years ago

HELP ASAP will give brainliest for answer

katrin2010 [14]

Answer:

This is the answer

x=π/10

6 0

2 years ago

An equilateral pentagon is a five-sided figure with equal side lengths. The

Ratling [72]

Answer: quit

Step-by-step explanation:

5 0

3 years ago

Round the following percentages to one decimal place.0.698%53.123%0.075%34.337%3.876%

balandron [24]

To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

$\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}$

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

$\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}$

4 0

1 year ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

3 0

3 years ago