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Mazyrski [523]
3 years ago
15

What is the expression of 3/4 percent divided between 7/4 and 2/4?

Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

85.714285 reapeating

Step-by-step explanation:

You might be interested in
Find the volume of a cone of radius 49cm and height 10cm​
den301095 [7]

Answer:

<h2> 25154.34{cm}^{3}</h2>

Step-by-step explanation:

Given,

Radius ( r ) = 49 cm

Height (h) = 10 cm

Volume of cone=?

Now,

Applying the formula to find the volume of cone:

\pi \:  {r}^{2}  \frac{h}{3}

Plugging the values,

\frac{22}{7}  \times  {49}^{2}  \times  \frac{10}{3}

\frac{22}{7} \times 2401 \times  \frac{10}{3}

Calculate

25153.34  \:  {cm}^{3}

Hope this helps...

Good luck on your assignment..

3 0
3 years ago
Read 2 more answers
Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if
Alborosie
\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}

\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0

\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1
4 0
4 years ago
9.675,9.25,9.325,9.5 least to greatest
max2010maxim [7]
9.25, 9.325, 9.5, 9.675
8 0
3 years ago
Read 2 more answers
In a certain year, 87% of all Caucasians in the U.S., 73% of all African-Americans, 73% of all Hispanics, and 83% of residents n
Vika [28.1K]

Answer:

73% of 13% which can also be depicted of .73*.13 which is .0949 which could also be 9.5%

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Simplify (y + 1)^5y + 1)^3​
kondor19780726 [428]

<em>Note: Your expression sounds a little unclear, so I am assuming your expression is </em>

\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3

<em>But, the procedure to solve the expressions involving exponents remains the same, so whatever the expression is, you may be able to get your concept clear. </em>

<em>In the end, I will solve </em><em>both expressions</em><em>.</em>

Answer:

Please check the explanation

Step-by-step explanation:

Given the expression

\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3

solving the expression

\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}

\left(y+1\right)^5\left(y+1\right)^3=\left(y+1\right)^{5+3}

                          =\left(y+1\right)^8

Therefore, we conclude that:

\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3=\left(y+1\right)^8

IF YOUR EXPRESSION IS THIS

                       ↓

\left(y\:+\:1\right)^{\left(5y+1\right)^3}

solving the expression

as

\left(a+b\right)^3=a^3+3a^2b+3ab^2+b^3

so

\left(5y+1\right)^3=125y^3+75y^2+15y+1

               =125y^3+75y^2+15y+1

Thus, the expression becomes

\left(y+1\right)^{\left(5y+1\right)^3}=\left(y+1\right)^{125y^3+75y^2+15y+1}

5 0
3 years ago
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