What value of y makes the equation true? -7/12=y/-36

Which point is the incenter of the triangle?

Likurg_2 [28]

The answer is A for this problem

6 0

2 years ago

4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B

AleksAgata [21]

Answer:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

$\hat p=\frac{63}{200}=0.315$ estimated proportion of lawyers had used some form of advertising for their business

$p_o=0.25$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

8 0

3 years ago

I need the answers to both. Will give brainiest!

miskamm [114]

Answer:

1. Number 1 and 2 and 4 is a function, 2. number 1 is a function

Step-by-step explanation:

1)To know if it's a function or not run vertical lines through multiple places of the graph. If it is a function every single time you do the vertical line test it should only go over the line once. If you do the vertical line test on 3 you will see that it went over the line on the graph, so we know not a function. Graphs 1, 2, and 4m however, are different, when you do the vertical line test on those graphs it only goes over them once.

2) Choice (1) is a function because when drawing vertical lines through the graph it only goes over one.

Choice (2) is not a function because when drawing vertical lines through the graph it covers two points on the graph.

Choice (3) is not a function because when drawing vertical lines through the graph it goes over multiple points.

Choice (4) is not a function because when a vertical line is drawn, it goes over more than one point on the graph.

The vertical test is a way to determine if it is a function.

When looking at a table functions are one-to-one and many-to-one

Non-functions are one-to-many and many-to-many

Hoped this helped you : )

5 0

2 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

zaharov [31]

Answer:

P(61≤ X≤94) = 49.85%

Step-by-step explanation:

From the given information:

The mean of the bell shaped fluorescent light bulb μ = 61

The standard deviation σ = 11

The objective of this question is to determine the approximate percentage of light bulb replacement requests numbering between 61 and 94 i.e P(61≤ X≤94)

Using the empirical (68-95-99.7)rule ;

At 68% , the data lies between μ - σ and μ + σ

i.e

61 - 11 and 61 + 11

50 and 72

At 95%, the data lies between μ - 2σ and μ + 2σ

i.e

61 - 2(11) and 61 + 2(11)

61 - 22 and 61 +22

39 and 83

At 99.7%, the data lies between μ - 3σ and μ + 3σ

i.e

61 - 3(11) and 61 + 3(11)

61 - 33 and 61 + 33

28 and 94

the probability equivalent to 94 is when P(28≤ X≤94) =99.7%

This implies that ,

P(28≤ X≤94) + P(61≤ X≤94) = 99.7%

P(28≤ X≤94) = P(61≤ X≤94) = 99.7 %

This is so because the distribution is symmetric about the mean

P(61≤ X≤94) = 99.7 %/2

P(61≤ X≤94) = 49.85%

5 0

2 years ago

What number replaces the ◊?

PolarNik [594]

Answer:

The answer is A.

15 + 4 + 3 = 15 + 7

3 0

3 years ago

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