Given that th<span>e coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) and the coordinates of the vertices of △D′E′F′ are D′(0, −1) , E′(−5, −1) , and F′(0, −3) .
Notice that the y-coordinates of the pre-image and that of the image are the same, which means that there is a reflection across the y-axis.
A refrection across the y-axis results in the change in sign of the x-coordinates of the pre-image and the image while the y-coordinate of the image remains the same as that of the pre-image.
A refrection across the y-axis of </span>△DEF with vertices D(2, −1) , E(7, −1) , and F(2, −3)
will result in and image with vertices (-2, -1), (-7, -1) and (-2, -3) respectively.
Notice that the x-coordinate of the final image △D′E′F′ with vertices <span>D′(0, −1) , E′(−5, −1) , and F′(0, −3) is 2 units greater than the vertices of the result of recting the pre-image across the y-axis.
This means that the result of refrecting the pre-image was shifted two places to the right.
Therefore, </span>the sequence of transformations that maps △DEF to △D′E′F′ are reflection across the y-axis and translation 2 units right.
Y =0.5x +2 The y-intercept is found by the coordinates (0,2) and the change is 0.5
The slope-intercept form of the linear function is y = m x + b , where m is the slope and b is y-intercept.
Here we have: y = 3 x - 3
a ) When y = 0
0 = 3 x - 3
- 3 x = - 3
x = ( - 3 ) : ( - 3 )
x = 1
When x = 0
y = 3 * 0 - 3
y = - 3
So x - intercept is ( 1, 0 ) and y-intercept is ( 0, - 3 ).
b ) The slope:
m = ( y2 - y1) / ( x2 - x1 ) =
= ( - 3 - 3 ) / ( 5- 7 ) = ( - 6 ) /( - 2 ) = 6 / 2 = 3
Answer: The slope m = 3 .
