What is the quotient of (x3-x2-17x-15) / (x-5)

In a carnival drawing, a green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10. There are 100 green tickets,

Rashid [163]

Answer:

D) 3:10

Step-by-step explanation:

Well only blues and yellows are at least $5. there are 25 yellows and 5 blues and if you add them together there's 30 in total. Now compare that 30 to 100 and you have 30:100. In the simplest form you have to divide both sides by 10 and it becomes 3:10.

3 0

2 years ago

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo

Aloiza [94]

Answer:

$a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]$

Step-by-step explanation:

a. -Given that:

$n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64$

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

$\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03$

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator, $\bar x_m-\bar x_f$ is calculated by the following following:

$\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

-And the margin of error, E at a 99% confidence can be calculated as:

$E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416$

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

$\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:

$CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]$

Hence, the 99% confidence interval is [51.2884,82.7716]

7 0

2 years ago

in a classroom, 1/6 of the students are wearing blue shirts and 2/3 are wearing white shirts. there are 36 students in the class

Zina [86]

The fraction indicating the number of students who are not wearing either blue or white shirt is:
1- 1/6- 2/3= 1/6.

36 students* (1/6)= 6 students.

There are 6 students who are not wearing either a blue or a white shirt.

Hope this helps~

5 0

3 years ago

Monday the low temperature in Bristol what is -5 Fahrenheit on Tuesday the low-temperature was 14 Fahrenheit how many degrees wa

icang [17]

To find your answer do 14+5 which is 19 so your answer is 19

7 0

3 years ago

5TH GRADE MATH HELP What is 4.873 rounded to the nearest hundredth? A. 4.87 B. 4.88 C. 4.9 D. 5

timama [110]

the answer is a becuse you tacke that little dot and you slid it to the left tow times

4 0

3 years ago

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