First Simplify addition and subtraction expressions: combining like terms. ...
Second Read and write an algebraic expression containing a variable. ...
Third Write word problems as algebraic expressions. ...
Fourth Read and write algebraic expressions using parentheses. ...
Last Evaluate one-step algebraic expressions by substitution.
9514 1404 393
Answer:
2.56
Step-by-step explanation:
Multiply by (1+6e^(-.7t))/1000:
2000/1000 = 1 +6e^(-0.07t)
1 = 6e^(-0.07t) . . . . . . . . . subtract 1
e^(0.07t) = 6 . . . . . . . . . . multiply by e^(0.07t)
0.07t = ln(6) . . . . . . . . . take the natural log
t = ln(6)/0.07 . . . . . . . divide by the coefficient of t
t ≈ 2.55966 ≈ 2.56
The function
... f(x) = (x+2)/(x-1) = 1 + 3/(x-1)
is symmetrical about the line y=x, hence is its own inverse.
We can evaluate the desired derivative directly.
... f'(x) -3/(x-1)²
so f'(2) is
... f'(2) = -3/(2-1)²
Answer:50
Step-by-step explanation:
Plug 7 in for x
Multiply 9 by 7
Solve like normal equation
