Please please help help me please please ASAP ASAP please ASAP thank you!!!

Eight less than a number y is ninety four

maria [59]

Y = a number
"is" means "equal to"

Equation:
Y - 8 = 94

Solving for Y:
Y - 8 = 94
Add 8 to both sides
Y = 102

Answer: Y = 102

Hope this helps!!

8 0

4 years ago

Gabriel invested $900 in an account paying an interest rate of 3 1/4 % compounded daily. Daniel invested $900 in an account payi

Helen [10]

Answer:

$40

Step-by-step explanation:

The earnings of Gabriel can be calculated with the formula:

P = Po * (1 + r/n)^(nt)

Where P = 900, r = 0.0325, n = 365 and t = 19

So we have:

P = 900 * (1 + 0.0325/365)^(365*19) = $1,668.81

The earnings of Daniel can be calculated with the formula:

P = Po * e^(rt)

Where Po = 900, r = 0.03375 and t = 19

So we have:

P = 900 * e^(0.03375*19) = $1,708.97

So the amount that Daniel will have more than Gabriel is:

1708.97 - 1668.81 = $40.16

Rounding to nearest dollar, the difference is $40

3 0

3 years ago

This figure represents a small brick that is to be covered on all sides with a striped fabric. How much fabric is needed to cove

kati45 [8]

For a question like this you need to find the surface area
The formula is :
b x w x h (base x width x height)

So you multiply 3 1/2 x 6 x 5 1/2 = 22.5

Answers 22.5

7 0

2 years ago

Read 2 more answers

Find the slope of the line that contains (−3,5) and (3,−9).

snow_lady [41]

The slope is this and that

5 0

3 years ago

Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.

Kobotan [32]

Answer:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=3.7$ represent the mean for athletes

$\bar X_{NA}=4.1$ represent the mean for non athletes

$s_{A}=1.1$ represent the sample standard deviation for athletes

$s_{NA}=1.3$ represent the sample standard deviation for non athletes

$n_{A}=32$ sample size for the group 2

$n_{NA}=45$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{NA}\geq 0$

Alternative hypothesis: $\mu_{A} - \mu_{NA}< 0$

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{NA}-2=32+45-2=75$

Since is a one left tailed test the p value would be:

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

5 0

3 years ago