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anyanavicka [17]

3 years ago

11

After three years, Elsie’s car had lost 1/3 of its original value. Two years later, it had lost an additional 1/4 of its origina

l value. If she bought the car for 3,600 dollars, what was the price it was worth after 5 years?

1 answer:

horrorfan [7]3 years ago

8 0

Answer:

1,500 dollars

Step-by-step explanation:

3,600 - 1/3(3600)=2,400

2,400 -1/4(3600)=$1,500

Hope this helps!

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A researcher has two percentages and wants to know if the percentages are statistically different. The researcher calculates the

love history [14]

Answer:

$p_v =2*P(Z>4.21) =2.55x10^{-5}$

And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

D) Are statistically different.

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Where $\mu_1$ and $\mu_2$ represent the percentages that we want to test on this case.

The statistic calculated is on this case was Z=4.21. Since we are conducting a two tailed test the p value can be founded on this way.

$p_v =2*P(Z>4.21) =2.55x10^{-5}$

And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

And the best option on this case would be:

D) Are statistically different.

4 0

3 years ago

What should be added in the polynomial x3-6x2+11x+8 so that it is completely divisible by 1-3x +x2

yanalaym [24]

Answer:

The value to be added to the polynomial x³ - 6·x² + 11·x + 8 so that it is completely divisible by 1 - 3·x + x² is -(x + 11)

Step-by-step explanation:

By long division, we have;

${\left ({x^{3}-6x^{2}+11x+8} \right )\div 1 - 3x + x^{2}}$ = x - 3

-(x³ - 3·x² + x)

-3·x² + 10·x + 8

-(-3·x² + 9·x -3)

x + 11

Therefore, -(x + 11) should be added to the polynomial x³ - 6·x² + 11·x + 8 so that it is completely divisible by 1 - 3·x + x².

That is (x³ - 6·x² + 11·x + 8 - x - 11) ÷ (1 - 3·x + x²) = x - 3.

5 0

3 years ago

Smo answer these and show work plz

suter [353]

Answer:

Step-by-step explanation:

1) multiply the three dimension

V = 7 x 2 x 4 = 56 cm^3

2) find the base area

base area = (9 x 3)/2 = 13,5 km^2

multiply the base area for the height

V = 13,5 x 5 = 67,5 km^3

3) find the trapezoid area

trapezoid area = [(base 1 + base 2) x h]/2 = [(4+6) x 1.7]/2 = 8.5 cm^2

mutiply the trapezoid area for the height that the priam would assume if the base will touch the ground

V = 8.5 x 4 = 34 cm^3

4) find the base area

base area = radius^2 x pi = 2^2 x pi = 12,57 yd^2

multiply the base area for the height

V= 12.57 x 6 = 75.40 yd^3

5) find the base area

base area = 9^2 x pi = 81 x pi = 254.47 ft^2

multiply the base area for the height

V = 254.47 x 5 = 1272.35 ft^3

6) multiply the three dimensions

V = 12 x 11 x 9 = 1188 yd^3

7) find the trapezoid area

trapezoid area = [(12+6) x 6.3]/2 = [20 x 6,3]/2 = 63 in^2

mutiply the trapezoid area for the height that the priam would assume if the base will touch the ground

V = 63 x 16 = 1008 in^3

8) find the base area

base area = (leg1 x leg 2)/2 = (4 x 3)/2 = 6 m^2

multiply the base area for the height

V = 6 x 9 = 54 m^3

4 0

3 years ago

Read 2 more answers

A region R is enclosed by the coordinate graph of y=k(x-5)^2. When this region is revolved around the x-axis, the solid has a vo

alexandr1967 [171]

K would equal 3.

Your welcome.

4 0

3 years ago

For circle Q, (DC) ̅ and (GC) ̅ are tangent line segments. Use the given information to solve for

luda_lava [24]

Arc DB = 2 ( angle DAB ) = 2 (35) = 70 degrees
Arc DG = 2 (Arc DB) = 2 (150) =150 degrees

Arc DAG = 360 - Arc DG = 360 - 150 = 210 degrees

Angle DCG = (210 - 150) /2 = 30 degrees
Angle DCB = 30/2 = 15 degrees<span />

6 0

3 years ago