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Olegator [25]
3 years ago
8

Tom's neighbor is fixing a section of his walkway. He has 32 bricks that he is placing in 8 equal rows. How many bricks will tom

's neighbor place in each row?
Mathematics
2 answers:
kykrilka [37]3 years ago
8 0
4 bricks in each row 32 divided by 8 equals 4nrows
igor_vitrenko [27]3 years ago
6 0
Tom's neighbor will place 4 bricks in each row.
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Each day, enough paperis recycledin the united statesto fill 15 miles of train boxcars.how many miles of boxcars could be filled
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15 x 7 days = 105 then multiply 5 weeks. 5 x 105 = 525 miles
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The points (-4,-4), (-4,4), (4,4), (4,-4) form a square on a coordinate plane. How long is a side length of a square?
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Read 2 more answers
14 times a number decreased By eight is 22 Increase by 20 times The same number
kotegsom [21]

Answer:

14x - 8 = 22 + 20x

x = -5

Step-by-step explanation:

Let "the number" be represented by x

Take each part of the statement and translate into algebraic form

"14 times a number" 14x

"decreased By eight" -8

"is" =

"22 Increased by" 22 +

"20 times The same number" 20x

Put the equation together. Solve for x by isolating.

(

14x - 8 = 22 + 20x

14x - 8 - 20x = 22 + 20x - 20x Subtract 20x from both sides

-6x - 8 = 22

-6x - 8 + 8 = 22 + 8  Add 8 to both sides

-6x = 30

-6x ÷ -6 = 30 ÷ -6  Divide both sides by -6

x = -5

4 0
3 years ago
Please help! (Numbers 1 and 2)
Svetradugi [14.3K]
1. is 8
2. is 4

Subtract them by the percentage
5 0
3 years ago
The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate
Schach [20]

Answer:

(a)0.16

(b)0.588

(c)[s_1$ s_2]=[0.75,$  0.25]

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix P^k.

(a)

P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}

If the system is initially running, the probability of the system being down in the next hour of operation is the (a_{12})th$ entry of the P^2$ matrix.

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, S=[s_1$  s_2]

[s_1$  s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$  s_2]

Using a calculator to raise matrix P to large numbers, we find that the value of P^k approaches [0.75 0.25]:

Furthermore,

[0.75$  0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$  0.25]

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

[s_1$ s_2]=[0.75$  0.25]

4 0
3 years ago
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