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Leno4ka [110]
3 years ago
14

Help me for brainetest

Mathematics
2 answers:
motikmotik3 years ago
7 0

The right answer is 1 1/6

look at the attached picture

hope it helps..

Good luck on your assignment

Solnce55 [7]3 years ago
5 0

Answer:

1 and 1/6

Step-by-step explanation:

if you simplify 6/6 is equal to 1 and the extra 1/6 is the fraction so the answer is 1 and 1/6

plz give me brainiest

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2. The width of a rectangle is 5 units less than the length. If the area is 150 square units, then find the dimensions of the re
xz_007 [3.2K]

Answer:

  • The length = x = 15 units
  • The width = x-5 = 10 units

Step-by-step explanation:

Let 'x' be the length of a rectangle

As the width of a rectangle is 5 units less than the length.

so

width of rectangle will be = w = x - 5 units

Area = 150 square units

Using the formula

Area = length × width

150=\left(x\right)\left(x-5\right)

150=x^2-5x

x^2-5x=150

Subtract 50 from both sides

x^2-5x-150=150-150

x^2-5x-150=0

\left(x+10\right)\left(x-15\right)=0

if

ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+10=0\quad \mathrm{or}\quad \:x-15=0

x=-10,\:x=15

As length can not be negative. so

x = 15 units

Hence,

The length = x = 15 units

The width = x-5 = 15-5 = 10 units

5 0
2 years ago
1A technical magazine stated that the mean retail cost of all models of a particular laptop was $600. A random sample of 10 stor
My name is Ann [436]

Answer:

Yes

Step-by-step explanation:

Given,

Population mean Z = 600

Sample mean, µ = 586.50

Size of the sample, n = 10

Standard deviation, σ = 26.77

The testing hypothesis is,

Null hypothesis = µ<600

Alternative hypothesis = µ≥600

The test statistics is the calculated value of Z,

(Z- µ)/(σ/√n)

= (600-586.50)/(26.77/√10)

= (13.5*3.1623)/26.77

= 42.691/26.77

= 1.5947

And at 5% level of significance, the table value of Z = 1.644

Here, calculated Z<Table value of Z, so we accept the null hypothesis.

So, the null hypothesis is accepted. The mean value of the laptop is less than 600.

3 0
3 years ago
Write the expression 12^-2 in simplest form.
olga2289 [7]

Answer:

Step-by-step explanation:

1/12^2 = 1/144

8 0
2 years ago
Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
Read 2 more answers
What is one thousand minus on hundred and ten
Alexeev081 [22]

Answer:

The answer is 890 . ...... :D

7 0
3 years ago
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