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3 years ago

Hai came someone help I too lazy to do it...

Mathematics

1 answer:

baherus [9]3 years ago

3 0

Answer: 4 Cups

I think in order to solve this, you would need to add up the fractions that they used. So it would be,

$\frac{1}{4}+\frac{1}{4}+\frac{3}{8}+\frac{3}{8}+\frac{5}{8}+\frac{5}{8}+\frac{5}{8}+\frac{7}{8}$ Transform the Expressions

$\frac{1+1}{4} +\frac{3+3+5+5+5+7}{8}$ Calculate the sum

$\frac{2}{4} +\frac{28}{8}$ Reduce

$\frac{1}{2}+\frac{7}{2}$ Transform the Expression

$\frac{1+7}{2}$ Calculate

$\frac{8}{2}$ Reduce the Fraction

$4$

Please mark brainliest if this helped you :)

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Answer:

155 women must be randomly selected.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

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Now, find the margin of error M as such

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In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The population standard deviation is known to be 28 lbs.

This means that $\sigma = 28$

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This is n for which M = 3.7. So

$M = z\frac{\sigma}{\sqrt{n}}$

$3.7 = 1.645\frac{28}{\sqrt{n}}$

$3.7\sqrt{n} = 1.645*28$

$\sqrt{n} = \frac{1.645*28}{3.7}$

$(\sqrt{n})^2 = (\frac{1.645*28}{3.7})^2$

$n = 154.97$

Rounding up:

155 women must be randomly selected.

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